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Python PackageId.validate_name方法代码示例

本文整理汇总了Python中pkgpanda.PackageId.validate_name方法的典型用法代码示例。如果您正苦于以下问题:Python PackageId.validate_name方法的具体用法?Python PackageId.validate_name怎么用?Python PackageId.validate_name使用的例子?那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在pkgpanda.PackageId的用法示例。


在下文中一共展示了PackageId.validate_name方法的1个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Python代码示例。

示例1: _get_package_list

# 需要导入模块: from pkgpanda import PackageId [as 别名]
# 或者: from pkgpanda.PackageId import validate_name [as 别名]
    def _get_package_list(treeinfo_dict, key, excludes=None):
        """Return a list of package name strings from treeinfo_dict by key.

        If key isn't present in treeinfo_dict, an empty list is returned.

        """
        excludes = excludes or list()
        package_list = treeinfo_dict.get(key, list())

        # Validate package list.
        if not isinstance(package_list, list):
            raise BuildError("{} must be either null (meaning don't use) or a list of package names.".format(key))
        for package_name in package_list:
            if not isinstance(package_name, str):
                raise BuildError("{} must be a list of strings. Found a {} with the value: {}".format(
                    key, type(package_name), package_name))

            try:
                PackageId.validate_name(package_name)
            except ValidationError as ex:
                raise BuildError("Invalid package name in {}: {}".format(key, package_name)) from ex

            if package_name in excludes:
                raise BuildError("Package found in both exclude and {}: {}".format(key, package_name))

        return package_list
开发者ID:alberts,项目名称:dcos,代码行数:28,代码来源:__init__.py


注:本文中的pkgpanda.PackageId.validate_name方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。