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Python Photo.title_slug方法代码示例

本文整理汇总了Python中photologue.models.Photo.title_slug方法的典型用法代码示例。如果您正苦于以下问题:Python Photo.title_slug方法的具体用法?Python Photo.title_slug怎么用?Python Photo.title_slug使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在photologue.models.Photo的用法示例。


在下文中一共展示了Photo.title_slug方法的4个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Python代码示例。

示例1: handle_uploaded_file

# 需要导入模块: from photologue.models import Photo [as 别名]
# 或者: from photologue.models.Photo import title_slug [as 别名]
def handle_uploaded_file(f,title):
    """ """
    photo = Photo()
    photo.title = u'%s %s' % (title, time_slug_string()) 
    photo.title_slug = time_slug_string()
    photo.image = f
    photo.save()
    return photo
开发者ID:jatsu,项目名称:cssocialprofile,代码行数:10,代码来源:views.py

示例2: uploadimagejson

# 需要导入模块: from photologue.models import Photo [as 别名]
# 或者: from photologue.models.Photo import title_slug [as 别名]
def uploadimagejson(request):
  p = Photo()
  if request.user.is_authenticated():
    if request.method == 'POST':
      pt = codegenerator()+codegenerator()
      p.image = request.FILES['file']
      p.title = pt
      p.title_slug = slugify(pt) #+codegenerator()
      p.save()
#  template = loader.get_template('redactorimageupload.html')
    params = { 'photo' : p }
#  context = RequestContext(request, params)  
  return render_to_response('redactorimageupload.html',params,context_instance = RequestContext(request))
开发者ID:emakarov,项目名称:blog-wl-school,代码行数:15,代码来源:views.py

示例3: loadUrlImage

# 需要导入模块: from photologue.models import Photo [as 别名]
# 或者: from photologue.models.Photo import title_slug [as 别名]
def loadUrlImage(url='', title='', tags='', format='jpg', slug=''):
    """ """
    if not url:
        url = 'http://irudiak.argazkiak.org/1d3023545b4051907e533648e66329f8_c.jpg'
        title = 'Kakalardoa'
        tags = 'test argazkiak'

    if not slug:
        slug = time_slug()

    if Photo.objects.filter(title_slug=slug):
        slug = time_slug_long()

    title = title[:99]
    if Photo.objects.filter(title=title):
        title = '%s %s' % (slug, title)[:90]
    
        
    image = _getUrlImage(url)

    if not image:
        return 0

    photo = Photo()
    photo.title = title[:100]
    photo.tags = tags
    photo.title_slug = slug
    
    try:
        image_t = Image.open(ContentFile(image.read()))
        image_t = image_t.convert("RGB")
        f=StringIO()
        image_t.save(f,"JPEG")
        f.seek(0)    
    
        photo.image.save('%s.%s' % (slug,format), ContentFile(f.read()))

    except Exception, e:
        print 'Errorea irudi honekin RGB', photo.title_slug, e
        return photo      
开发者ID:jatsu,项目名称:cssocialprofile,代码行数:42,代码来源:load_images.py

示例4: loadUrlImage

# 需要导入模块: from photologue.models import Photo [as 别名]
# 或者: from photologue.models.Photo import title_slug [as 别名]
def loadUrlImage(url='', title='', tags='', format='jpg'):
    """ """
    if not url:
        url = 'http://ahotsak.com/files/Proiektuak/beasain.jpg'
        title = 'Beasain'
        tags = 'proiektua beasain'

    slug = slugify(title)[:50]

    image = _getUrlImage(url)

    if not image:
        return 0

    if Photo.objects.filter(title_slug=slug):
        for i in range(1,1000):
            new_slug = '%s-%d' % (slug,i)
            new_title = '%s (%d)' % (title,i)
            if not Photo.objects.filter(title_slug=new_slug):
                slug = new_slug
                title = new_title
                break
        
    photo = Photo()
    photo.title = title
    photo.tags = tags
    photo.title_slug = slug
    photo.image.save('%s.%s' % (slug,format), ContentFile(image.read()))
    try:
        photo.save()
    except:
        print 'Errorea irudi honekin', photo.title
        """
        photo.title_slug = photo.title_slug + '_2'         
        photo.save()
        """
    return photo
开发者ID:aitzol,项目名称:csnews,代码行数:39,代码来源:load_images.py


注:本文中的photologue.models.Photo.title_slug方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。