本文整理汇总了Python中openpyxl.cell.Cell.formula方法的典型用法代码示例。如果您正苦于以下问题：Python Cell.formula方法的具体用法？Python Cell.formula怎么用？Python Cell.formula使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类openpyxl.cell.Cell的用法示例。
在下文中一共展示了Cell.formula方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: parse_cell
# 需要导入模块: from openpyxl.cell import Cell [as 别名]
# 或者: from openpyxl.cell.Cell import formula [as 别名]
def parse_cell(self, element):
value = element.find(self.VALUE_TAG)
if value is not None:
value = value.text
formula = element.find(self.FORMULA_TAG)
data_type = element.get('t', 'n')
coordinate = element.get('r')
style_id = element.get('s')
formula_value = None
# assign formula to cell value unless only the data is desired
if formula is not None and not self.data_only:
data_type = 'f'
if formula.text:
formula_value = "=" + formula.text
else:
formula_value = "="
formula_type = formula.get('t')
if formula_type:
if formula_type != "shared":
self.ws.formula_attributes[coordinate] = dict(formula.attrib)
else:
si = formula.get('si') # Shared group index for shared formulas
# The spec (18.3.1.40) defines shared formulae in
# terms of the following:
#
# `master`: "The first formula in a group of shared
# formulas"
# `ref`: "Range of cells which the formula applies
# to." It's a required attribute on the master
# cell, forbidden otherwise.
# `shared cell`: "A cell is shared only when si is
# used and t is `shared`."
#
# Whether to use the cell's given formula or the
# master's depends on whether the cell is shared,
# whether it's in the ref, and whether it defines its
# own formula, as follows:
#
# Shared? Has formula? | In ref Not in ref
# ========= ==============|======== ===============
# Yes Yes | master impl. defined
# No Yes | own own
# Yes No | master impl. defined
# No No | ?? N/A
#
# The ?? is because the spec is silent on this issue,
# though my inference is that the cell does not
# receive a formula at all.
#
# For this implementation, we are using the master
# formula in the two "impl. defined" cases and no
# formula in the "??" case. This choice of
# implementation allows us to disregard the `ref`
# parameter altogether, and does not require
# computing expressions like `C5 in A1:D6`.
# Presumably, Excel does not generate spreadsheets
# with such contradictions.
if si in self.shared_formula_masters:
trans = self.shared_formula_masters[si]
formula_value = trans.translate_formula(coordinate)
else:
self.shared_formula_masters[si] = Translator(formula_value, coordinate)
style_array = None
if style_id is not None:
style_id = int(style_id)
style_array = self.styles[style_id]
row, column = coordinate_to_tuple(coordinate)
cell = Cell(self.ws, row=row, col_idx=column, style_array=style_array)
self.ws._cells[(row, column)] = cell
cell.formula = formula_value
if value is not None:
if data_type == 'n':
value = _cast_number(value)
elif data_type == 'b':
value = bool(int(value))
elif data_type == 's':
value = self.shared_strings[int(value)]
elif data_type == 'str':
data_type = 's'
else:
if data_type == 'inlineStr':
data_type = 's'
child = element.find(self.INLINE_STRING)
if child is None:
child = element.find(self.INLINE_RICHTEXT)
if child is not None:
value = child.text
if self.guess_types or value is None:
cell.value = value
#.........这里部分代码省略.........