Python numeric.alltrue函数代码示例

def diag_indices_from(arr):
    """
    Return the indices to access the main diagonal of an n-dimensional array.

    See `diag_indices` for full details.

    Parameters
    ----------
    arr : array, at least 2-D

    See Also
    --------
    diag_indices

    Notes
    -----
    .. versionadded:: 1.4.0

    """

    if not arr.ndim >= 2:
        raise ValueError("input array must be at least 2-d")
    # For more than d=2, the strided formula is only valid for arrays with
    # all dimensions equal, so we check first.
    if not alltrue(diff(arr.shape) == 0):
        raise ValueError("All dimensions of input must be of equal length")

    return diag_indices(arr.shape[0], arr.ndim)

def poly(seq_of_zeros):
    """ Return a sequence representing a polynomial given a sequence of roots.

    If the input is a matrix, return the characteristic polynomial.

    Example:

        >>> b = roots([1,3,1,5,6])
        >>> poly(b)
        array([ 1.,  3.,  1.,  5.,  6.])

    """
    seq_of_zeros = atleast_1d(seq_of_zeros)
    sh = seq_of_zeros.shape
    if len(sh) == 2 and sh[0] == sh[1]:
        seq_of_zeros = _eigvals(seq_of_zeros)
    elif len(sh) ==1:
        pass
    else:
        raise ValueError, "input must be 1d or square 2d array."

    if len(seq_of_zeros) == 0:
        return 1.0

    a = [1]
    for k in range(len(seq_of_zeros)):
        a = NX.convolve(a, [1, -seq_of_zeros[k]], mode='full')

    if issubclass(a.dtype.type, NX.complexfloating):
        # if complex roots are all complex conjugates, the roots are real.
        roots = NX.asarray(seq_of_zeros, complex)
        pos_roots = sort_complex(NX.compress(roots.imag > 0, roots))
        neg_roots = NX.conjugate(sort_complex(
                                        NX.compress(roots.imag < 0,roots)))
        if (len(pos_roots) == len(neg_roots) and
            NX.alltrue(neg_roots == pos_roots)):
            a = a.real.copy()

    return a

#.........这里部分代码省略.........
        1D array of polynomial coefficients from highest to lowest degree:

        ``c[0] * x**(N) + c[1] * x**(N-1) + ... + c[N-1] * x + c[N]``
        where c[0] always equals 1.

    Raises
    ------
    ValueError
        If input is the wrong shape (the input must be a 1-D or square
        2-D array).

    See Also
    --------
    polyval : Evaluate a polynomial at a point.
    roots : Return the roots of a polynomial.
    polyfit : Least squares polynomial fit.
    poly1d : A one-dimensional polynomial class.

    Notes
    -----
    Specifying the roots of a polynomial still leaves one degree of
    freedom, typically represented by an undetermined leading
    coefficient. [1]_ In the case of this function, that coefficient -
    the first one in the returned array - is always taken as one. (If
    for some reason you have one other point, the only automatic way
    presently to leverage that information is to use ``polyfit``.)

    The characteristic polynomial, :math:`p_a(t)`, of an `n`-by-`n`
    matrix **A** is given by

        :math:`p_a(t) = \\mathrm{det}(t\\, \\mathbf{I} - \\mathbf{A})`,

    where **I** is the `n`-by-`n` identity matrix. [2]_

    References
    ----------
    .. [1] M. Sullivan and M. Sullivan, III, "Algebra and Trignometry,
       Enhanced With Graphing Utilities," Prentice-Hall, pg. 318, 1996.

    .. [2] G. Strang, "Linear Algebra and Its Applications, 2nd Edition,"
       Academic Press, pg. 182, 1980.

    Examples
    --------
    Given a sequence of a polynomial's zeros:

    >>> np.poly((0, 0, 0)) # Multiple root example
    array([1, 0, 0, 0])

    The line above represents z**3 + 0*z**2 + 0*z + 0.

    >>> np.poly((-1./2, 0, 1./2))
    array([ 1.  ,  0.  , -0.25,  0.  ])

    The line above represents z**3 - z/4

    >>> np.poly((np.random.random(1.)[0], 0, np.random.random(1.)[0]))
    array([ 1.        , -0.77086955,  0.08618131,  0.        ]) #random

    Given a square array object:

    >>> P = np.array([[0, 1./3], [-1./2, 0]])
    >>> np.poly(P)
    array([ 1.        ,  0.        ,  0.16666667])

    Or a square matrix object:

    >>> np.poly(np.matrix(P))
    array([ 1.        ,  0.        ,  0.16666667])

    Note how in all cases the leading coefficient is always 1.

    """
    seq_of_zeros = atleast_1d(seq_of_zeros)
    sh = seq_of_zeros.shape
    if len(sh) == 2 and sh[0] == sh[1] and sh[0] != 0:
        seq_of_zeros = eigvals(seq_of_zeros)
    elif len(sh) == 1:
        pass
    else:
        raise ValueError("input must be 1d or square 2d array.")

    if len(seq_of_zeros) == 0:
        return 1.0

    a = [1]
    for k in range(len(seq_of_zeros)):
        a = NX.convolve(a, [1, -seq_of_zeros[k]], mode='full')

    if issubclass(a.dtype.type, NX.complexfloating):
        # if complex roots are all complex conjugates, the roots are real.
        roots = NX.asarray(seq_of_zeros, complex)
        pos_roots = sort_complex(NX.compress(roots.imag > 0, roots))
        neg_roots = NX.conjugate(sort_complex(
                                        NX.compress(roots.imag < 0,roots)))
        if (len(pos_roots) == len(neg_roots) and
            NX.alltrue(neg_roots == pos_roots)):
            a = a.real.copy()

    return a

 def __eq__(self, other):
     return NX.alltrue(self.coeffs == other.coeffs)

#.........这里部分代码省略.........

    Parameters
    ----------
    a : array, at least 2-D.
      Array whose diagonal is to be filled, it gets modified in-place.

    val : scalar
      Value to be written on the diagonal, its type must be compatible with
      that of the array a.

    wrap: bool For tall matrices in NumPy version up to 1.6.2, the
      diagonal "wrapped" after N columns. You can have this behavior
      with this option. This affect only tall matrices.

    See also
    --------
    diag_indices, diag_indices_from

    Notes
    -----
    .. versionadded:: 1.4.0

    This functionality can be obtained via `diag_indices`, but internally
    this version uses a much faster implementation that never constructs the
    indices and uses simple slicing.

    Examples
    --------
    >>> a = np.zeros((3, 3), int)
    >>> np.fill_diagonal(a, 5)
    >>> a
    array([[5, 0, 0],
           [0, 5, 0],
           [0, 0, 5]])

    The same function can operate on a 4-D array:

    >>> a = np.zeros((3, 3, 3, 3), int)
    >>> np.fill_diagonal(a, 4)

    We only show a few blocks for clarity:

    >>> a[0, 0]
    array([[4, 0, 0],
           [0, 0, 0],
           [0, 0, 0]])
    >>> a[1, 1]
    array([[0, 0, 0],
           [0, 4, 0],
           [0, 0, 0]])
    >>> a[2, 2]
    array([[0, 0, 0],
           [0, 0, 0],
           [0, 0, 4]])

    # tall matrices no wrap
    >>> a = np.zeros((5, 3),int)
    >>> fill_diagonal(a, 4)
    array([[4, 0, 0],
           [0, 4, 0],
           [0, 0, 4],
           [0, 0, 0],
           [0, 0, 0]])

    # tall matrices wrap
    >>> a = np.zeros((5, 3),int)
    >>> fill_diagonal(a, 4)
    array([[4, 0, 0],
           [0, 4, 0],
           [0, 0, 4],
           [0, 0, 0],
           [4, 0, 0]])

    # wide matrices
    >>> a = np.zeros((3, 5),int)
    >>> fill_diagonal(a, 4)
    array([[4, 0, 0, 0, 0],
           [0, 4, 0, 0, 0],
           [0, 0, 4, 0, 0]])

    """
    if a.ndim < 2:
        raise ValueError("array must be at least 2-d")
    end = None
    if a.ndim == 2:
        # Explicit, fast formula for the common case.  For 2-d arrays, we
        # accept rectangular ones.
        step = a.shape[1] + 1
        # This is needed to don't have tall matrix have the diagonal wrap.
        if not wrap:
            end = a.shape[1] * a.shape[1]
    else:
        # For more than d=2, the strided formula is only valid for arrays with
        # all dimensions equal, so we check first.
        if not alltrue(diff(a.shape) == 0):
            raise ValueError("All dimensions of input must be of equal length")
        step = 1 + (cumprod(a.shape[:-1])).sum()

    # Write the value out into the diagonal.
    a.flat[:end:step] = val

def poly(seq_of_zeros):
    """
    Return polynomial coefficients given a sequence of roots.

    Calculate the coefficients of a polynomial given the zeros
    of the polynomial.

    If a square matrix is given, then the coefficients for
    characteristic equation of the matrix, defined by
    :math:`\\mathrm{det}(\\mathbf{A} - \\lambda \\mathbf{I})`,
    are returned.

    Parameters
    ----------
    seq_of_zeros : ndarray
        A sequence of polynomial roots or a square matrix.

    Returns
    -------
    coefs : ndarray
        A sequence of polynomial coefficients representing the polynomial

        :math:`\\mathrm{coefs}[0] x^{n-1} + \\mathrm{coefs}[1] x^{n-2} +
                      ... + \\mathrm{coefs}[2] x + \\mathrm{coefs}[n]`

    See Also
    --------
    numpy.poly1d : A one-dimensional polynomial class.
    numpy.roots : Return the roots of the polynomial coefficients in p
    numpy.polyfit : Least squares polynomial fit

    Examples
    --------
    Given a sequence of polynomial zeros,

    >>> b = np.roots([1, 3, 1, 5, 6])
    >>> np.poly(b)
    array([ 1.,  3.,  1.,  5.,  6.])

    Given a square matrix,

    >>> P = np.array([[19, 3], [-2, 26]])
    >>> np.poly(P)
    array([   1.,  -45.,  500.])

    """
    seq_of_zeros = atleast_1d(seq_of_zeros)
    sh = seq_of_zeros.shape
    if len(sh) == 2 and sh[0] == sh[1]:
        seq_of_zeros = eigvals(seq_of_zeros)
    elif len(sh) ==1:
        pass
    else:
        raise ValueError, "input must be 1d or square 2d array."

    if len(seq_of_zeros) == 0:
        return 1.0

    a = [1]
    for k in range(len(seq_of_zeros)):
        a = NX.convolve(a, [1, -seq_of_zeros[k]], mode='full')

    if issubclass(a.dtype.type, NX.complexfloating):
        # if complex roots are all complex conjugates, the roots are real.
        roots = NX.asarray(seq_of_zeros, complex)
        pos_roots = sort_complex(NX.compress(roots.imag > 0, roots))
        neg_roots = NX.conjugate(sort_complex(
                                        NX.compress(roots.imag < 0,roots)))
        if (len(pos_roots) == len(neg_roots) and
            NX.alltrue(neg_roots == pos_roots)):
            a = a.real.copy()

    return a

def fill_diagonal(a, val):
    """Fill the main diagonal of the given array of any dimensionality.

    For an array with ndim > 2, the diagonal is the list of locations with
    indices a[i,i,...,i], all identical.

    This function modifies the input array in-place, it does not return a
    value.

    This functionality can be obtained via diag_indices(), but internally this
    version uses a much faster implementation that never constructs the indices
    and uses simple slicing.

    Parameters
    ----------
    a : array, at least 2-dimensional.
      Array whose diagonal is to be filled, it gets modified in-place.

    val : scalar
      Value to be written on the diagonal, its type must be compatible with
      that of the array a.

    See also
    --------
    diag_indices, diag_indices_from

    Notes
    -----
    .. versionadded:: 1.4.0

    Examples
    --------
    >>> a = zeros((3,3),int)
    >>> fill_diagonal(a,5)
    >>> a
    array([[5, 0, 0],
           [0, 5, 0],
           [0, 0, 5]])

    The same function can operate on a 4-d array:
    >>> a = zeros((3,3,3,3),int)
    >>> fill_diagonal(a,4)

    We only show a few blocks for clarity:
    >>> a[0,0]
    array([[4, 0, 0],
           [0, 0, 0],
           [0, 0, 0]])
    >>> a[1,1]
    array([[0, 0, 0],
           [0, 4, 0],
           [0, 0, 0]])
    >>> a[2,2]
    array([[0, 0, 0],
           [0, 0, 0],
           [0, 0, 4]])

    """
    if a.ndim < 2:
        raise ValueError("array must be at least 2-d")
    if a.ndim == 2:
        # Explicit, fast formula for the common case.  For 2-d arrays, we
        # accept rectangular ones.
        step = a.shape[1] + 1
    else:
        # For more than d=2, the strided formula is only valid for arrays with
        # all dimensions equal, so we check first.
        if not alltrue(diff(a.shape) == 0):
            raise ValueError("All dimensions of input must be of equal length")
        step = 1 + (cumprod(a.shape[:-1])).sum()

    # Write the value out into the diagonal.
    a.flat[::step] = val