本文整理汇总了Python中neurokernel.pattern.Interface.is_in_interfaces方法的典型用法代码示例。如果您正苦于以下问题：Python Interface.is_in_interfaces方法的具体用法？Python Interface.is_in_interfaces怎么用？Python Interface.is_in_interfaces使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类neurokernel.pattern.Interface的用法示例。
在下文中一共展示了Interface.is_in_interfaces方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: test_is_in_interfaces
# 需要导入模块: from neurokernel.pattern import Interface [as 别名]
# 或者: from neurokernel.pattern.Interface import is_in_interfaces [as 别名]
def test_is_in_interfaces(self):
# Selector with multiple levels:
i = Interface('/foo[0:3]')
i['/foo[0]', 'interface', 'io'] = [0, 'in']
i['/foo[1:3]', 'interface', 'io'] = [0, 'out']
assert i.is_in_interfaces('/foo[0:3]') == True
assert i.is_in_interfaces('/foo[0:4]') == False
assert i.is_in_interfaces('/foo') == False
# Selector with single level:
i = Interface('/[foo,bar]')
i['/foo', 'interface', 'io'] = [0, 'in']
i['/bar', 'interface', 'io'] = [1, 'out']
assert i.is_in_interfaces('/foo') == True
assert i.is_in_interfaces('/qux') == False
# Selectors comprising identifiers with different numbers of levels
i = Interface('/foo,/bar[0:3]')
i['/foo', 'interface', 'io'] = [0, 'in']
i['/bar[0:3]', 'interface', 'io'] = [1, 'out']
assert i.is_in_interfaces('/foo') == True
assert i.is_in_interfaces('/bar[0]') == True
assert i.is_in_interfaces('/bar') == False