本文整理汇总了Python中kafka.SimpleConsumer.count_since_commit方法的典型用法代码示例。如果您正苦于以下问题：Python SimpleConsumer.count_since_commit方法的具体用法？Python SimpleConsumer.count_since_commit怎么用？Python SimpleConsumer.count_since_commit使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类kafka.SimpleConsumer的用法示例。
在下文中一共展示了SimpleConsumer.count_since_commit方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: test_simple_consumer_commit_does_not_raise
# 需要导入模块: from kafka import SimpleConsumer [as 别名]
# 或者: from kafka.SimpleConsumer import count_since_commit [as 别名]
def test_simple_consumer_commit_does_not_raise(self):
client = MagicMock()
client.get_partition_ids_for_topic.return_value = [0, 1]
def mock_offset_fetch_request(group, payloads, **kwargs):
return [OffsetFetchResponsePayload(p.topic, p.partition, 0, b'', 0) for p in payloads]
client.send_offset_fetch_request.side_effect = mock_offset_fetch_request
def mock_offset_commit_request(group, payloads, **kwargs):
raise FailedPayloadsError(payloads[0])
client.send_offset_commit_request.side_effect = mock_offset_commit_request
consumer = SimpleConsumer(client, group='foobar',
topic='topic', partitions=[0, 1],
auto_commit=False)
# Mock internal commit check
consumer.count_since_commit = 10
# This should not raise an exception
self.assertFalse(consumer.commit(partitions=[0, 1]))