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Python BlockedRoom.find_first方法代码示例

本文整理汇总了Python中indico.modules.rb.models.blocked_rooms.BlockedRoom.find_first方法的典型用法代码示例。如果您正苦于以下问题:Python BlockedRoom.find_first方法的具体用法?Python BlockedRoom.find_first怎么用?Python BlockedRoom.find_first使用的例子?那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在indico.modules.rb.models.blocked_rooms.BlockedRoom的用法示例。


在下文中一共展示了BlockedRoom.find_first方法的1个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Python代码示例。

示例1: validate_blocked_rooms

# 需要导入模块: from indico.modules.rb.models.blocked_rooms import BlockedRoom [as 别名]
# 或者: from indico.modules.rb.models.blocked_rooms.BlockedRoom import find_first [as 别名]
    def validate_blocked_rooms(self, field):
        try:
            field.data = map(int, field.data)
        except Exception as e:
            # In case someone sent crappy data
            raise ValidationError(str(e))

        # Make sure all room ids are valid
        if len(field.data) != Room.find(Room.id.in_(field.data)).count():
            raise ValidationError('Invalid rooms')

        if hasattr(self, '_blocking'):
            start_date = self._blocking.start_date
            end_date = self._blocking.end_date
            blocking_id = self._blocking.id
        else:
            start_date = self.start_date.data
            end_date = self.end_date.data
            blocking_id = None

        overlap = BlockedRoom.find_first(
            BlockedRoom.room_id.in_(field.data),
            BlockedRoom.state != BlockedRoom.State.rejected,
            Blocking.start_date <= end_date,
            Blocking.end_date >= start_date,
            Blocking.id != blocking_id,
            _join=Blocking
        )
        if overlap:
            msg = 'Your blocking for {} is overlapping with another blocking.'.format(overlap.room.full_name)
            raise ValidationError(msg)
开发者ID:bkolobara,项目名称:indico,代码行数:33,代码来源:blockings.py


注:本文中的indico.modules.rb.models.blocked_rooms.BlockedRoom.find_first方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。