本文整理汇总了Python中indico.modules.auth.Identity.find_first方法的典型用法代码示例。如果您正苦于以下问题：Python Identity.find_first方法的具体用法？Python Identity.find_first怎么用？Python Identity.find_first使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类indico.modules.auth.Identity的用法示例。
在下文中一共展示了Identity.find_first方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: _original_user
# 需要导入模块: from indico.modules.auth import Identity [as 别名]
# 或者: from indico.modules.auth.Identity import find_first [as 别名]
def _original_user(self):
# A proper user, with an id that can be mapped directly to sqlalchemy
if isinstance(self.id, int) or self.id.isdigit():
return User.get(int(self.id))
# A user who had no real indico account but an ldap identifier/email.
# In this case we try to find his real user and replace the ID of this object
# with that user's ID.
data = self.id.split(':')
# TODO: Once everything is in SQLAlchemy this whole thing needs to go away!
user = None
if data[0] == 'LDAP':
identifier = data[1]
email = data[2]
# You better have only one ldap provider or at least different identifiers ;)
identity = Identity.find_first(Identity.provider != 'indico', Identity.identifier == identifier)
if identity:
user = identity.user
elif data[0] == 'Nice':
email = data[1]
else:
return None
if not user:
user = User.find_first(User.all_emails.contains(email))
if user:
self._old_id = self.id
self.id = str(user.id)
logger.info("Updated legacy user id (%s => %s)", self._old_id, self.id)
return user