本文整理汇总了Python中immutable.ImmutableMatrix._new方法的典型用法代码示例。如果您正苦于以下问题:Python ImmutableMatrix._new方法的具体用法?Python ImmutableMatrix._new怎么用?Python ImmutableMatrix._new使用的例子?那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类immutable.ImmutableMatrix
的用法示例。
在下文中一共展示了ImmutableMatrix._new方法的6个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: as_immutable
# 需要导入模块: from immutable import ImmutableMatrix [as 别名]
# 或者: from immutable.ImmutableMatrix import _new [as 别名]
def as_immutable(self):
"""Returns an Immutable version of this Matrix
"""
from immutable import ImmutableMatrix as cls
if self.rows:
return cls._new(self.tolist())
return cls._new(0, self.cols, [])
示例2: zeros
# 需要导入模块: from immutable import ImmutableMatrix [as 别名]
# 或者: from immutable.ImmutableMatrix import _new [as 别名]
def zeros(cls, r, c=None):
"""Return an r x c matrix of zeros, square if c is omitted."""
if is_sequence(r):
SymPyDeprecationWarning(
feature="The syntax zeros([%i, %i])" % tuple(r),
useinstead="zeros(%i, %i)." % tuple(r),
issue=3381, deprecated_since_version="0.7.2",
).warn()
r, c = r
else:
c = r if c is None else c
r = as_int(r)
c = as_int(c)
return cls._new(r, c, [S.Zero]*r*c)
示例3: __new__
# 需要导入模块: from immutable import ImmutableMatrix [as 别名]
# 或者: from immutable.ImmutableMatrix import _new [as 别名]
def __new__(cls, *args, **kwargs):
return cls._new(*args, **kwargs)
示例4: eye
# 需要导入模块: from immutable import ImmutableMatrix [as 别名]
# 或者: from immutable.ImmutableMatrix import _new [as 别名]
def eye(cls, n):
"""Return an n x n identity matrix."""
n = as_int(n)
mat = [S.Zero]*n*n
mat[::n + 1] = [S.One]*n
return cls._new(n, n, mat)
示例5: diag
# 需要导入模块: from immutable import ImmutableMatrix [as 别名]
# 或者: from immutable.ImmutableMatrix import _new [as 别名]
#.........这里部分代码省略.........
[0, 2, 0]
[0, 0, 3]
>>> diag(*[1, 2, 3])
[1, 0, 0]
[0, 2, 0]
[0, 0, 3]
The diagonal elements can be matrices; diagonal filling will
continue on the diagonal from the last element of the matrix:
>>> from sympy.abc import x, y, z
>>> a = Matrix([x, y, z])
>>> b = Matrix([[1, 2], [3, 4]])
>>> c = Matrix([[5, 6]])
>>> diag(a, 7, b, c)
[x, 0, 0, 0, 0, 0]
[y, 0, 0, 0, 0, 0]
[z, 0, 0, 0, 0, 0]
[0, 7, 0, 0, 0, 0]
[0, 0, 1, 2, 0, 0]
[0, 0, 3, 4, 0, 0]
[0, 0, 0, 0, 5, 6]
When diagonal elements are lists, they will be treated as arguments
to Matrix:
>>> diag([1, 2, 3], 4)
[1, 0]
[2, 0]
[3, 0]
[0, 4]
>>> diag([[1, 2, 3]], 4)
[1, 2, 3, 0]
[0, 0, 0, 4]
A given band off the diagonal can be made by padding with a
vertical or horizontal "kerning" vector:
>>> hpad = ones(0, 2)
>>> vpad = ones(2, 0)
>>> diag(vpad, 1, 2, 3, hpad) + diag(hpad, 4, 5, 6, vpad)
[0, 0, 4, 0, 0]
[0, 0, 0, 5, 0]
[1, 0, 0, 0, 6]
[0, 2, 0, 0, 0]
[0, 0, 3, 0, 0]
The type is mutable by default but can be made immutable by setting
the ``mutable`` flag to False:
>>> type(diag(1))
<class 'sympy.matrices.dense.MutableDenseMatrix'>
>>> from sympy.matrices import ImmutableMatrix
>>> type(diag(1, cls=ImmutableMatrix))
<class 'sympy.matrices.immutable.ImmutableMatrix'>
See Also
========
eye
"""
from sparse import MutableSparseMatrix
cls = kwargs.pop('cls', None)
if cls is None:
from dense import Matrix as cls
if kwargs:
raise ValueError('unrecognized keyword%s: %s' % (
's' if len(kwargs) > 1 else '',
', '.join(kwargs.keys())))
rows = 0
cols = 0
values = list(values)
for i in range(len(values)):
m = values[i]
if isinstance(m, MatrixBase):
rows += m.rows
cols += m.cols
elif is_sequence(m):
m = values[i] = Matrix(m)
rows += m.rows
cols += m.cols
else:
rows += 1
cols += 1
res = MutableSparseMatrix.zeros(rows, cols)
i_row = 0
i_col = 0
for m in values:
if isinstance(m, MatrixBase):
res[i_row:i_row + m.rows, i_col:i_col + m.cols] = m
i_row += m.rows
i_col += m.cols
else:
res[i_row, i_col] = m
i_row += 1
i_col += 1
return cls._new(res)
示例6: eye
# 需要导入模块: from immutable import ImmutableMatrix [as 别名]
# 或者: from immutable.ImmutableMatrix import _new [as 别名]
def eye(cls, n):
"""Return an n x n identity matrix."""
n = as_int(n)
mat = [cls._sympify(0)]*n*n
mat[::n + 1] = [cls._sympify(1)]*n
return cls._new(n, n, mat)