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Python metadef_resource_type.ResourceTypeAssociation类代码示例

本文整理汇总了Python中glance.api.v2.model.metadef_resource_type.ResourceTypeAssociation的典型用法代码示例。如果您正苦于以下问题:Python ResourceTypeAssociation类的具体用法?Python ResourceTypeAssociation怎么用?Python ResourceTypeAssociation使用的例子?那么恭喜您, 这里精选的类代码示例或许可以为您提供帮助。


在下文中一共展示了ResourceTypeAssociation类的7个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Python代码示例。

示例1: show

    def show(self, req, namespace, filters=None):
        try:
            # Get namespace
            ns_repo = self.gateway.get_metadef_namespace_repo(req.context)
            namespace_obj = ns_repo.get(namespace)
            namespace_detail = Namespace.to_wsme_model(
                namespace_obj,
                get_namespace_href(namespace_obj),
                self.ns_schema_link)
            ns_filters = dict()
            ns_filters['namespace'] = namespace

            # Get objects
            object_repo = self.gateway.get_metadef_object_repo(req.context)
            db_metaobject_list = object_repo.list(filters=ns_filters)
            object_list = [MetadefObject.to_wsme_model(
                db_metaobject,
                get_object_href(namespace, db_metaobject),
                self.obj_schema_link) for db_metaobject in db_metaobject_list]
            if object_list:
                namespace_detail.objects = object_list

            # Get resource type associations
            rs_repo = self.gateway.get_metadef_resource_type_repo(req.context)
            db_resource_type_list = rs_repo.list(filters=ns_filters)
            resource_type_list = [ResourceTypeAssociation.to_wsme_model(
                resource_type) for resource_type in db_resource_type_list]
            if resource_type_list:
                namespace_detail.resource_type_associations = (
                    resource_type_list)

            # Get properties
            prop_repo = self.gateway.get_metadef_property_repo(req.context)
            db_properties = prop_repo.list(filters=ns_filters)
            property_list = Namespace.to_model_properties(db_properties)
            if property_list:
                namespace_detail.properties = property_list

            if filters and filters['resource_type']:
                namespace_detail = self._prefix_property_name(
                    namespace_detail, filters['resource_type'])

            # Get tags
            tag_repo = self.gateway.get_metadef_tag_repo(req.context)
            db_metatag_list = tag_repo.list(filters=ns_filters)
            tag_list = [MetadefTag(**{'name': db_metatag.name})
                        for db_metatag in db_metatag_list]
            if tag_list:
                namespace_detail.tags = tag_list

        except exception.Forbidden as e:
            LOG.debug("User not permitted to show metadata namespace "
                      "'%s'", namespace)
            raise webob.exc.HTTPForbidden(explanation=e.msg)
        except exception.NotFound as e:
            raise webob.exc.HTTPNotFound(explanation=e.msg)
        except Exception as e:
            LOG.error(encodeutils.exception_to_unicode(e))
            raise webob.exc.HTTPInternalServerError()
        return namespace_detail
开发者ID:mahak,项目名称:glance,代码行数:60,代码来源:metadef_namespaces.py

示例2: get_schema

def get_schema():
    properties = _get_base_properties()
    mandatory_attrs = ResourceTypeAssociation.get_mandatory_attrs()
    schema = glance.schema.Schema(
        'resource_type_association',
        properties,
        required=mandatory_attrs,
    )
    return schema
开发者ID:samueldmq,项目名称:glance,代码行数:9,代码来源:test_metadef_resourcetypes.py

示例3: index

    def index(self, req, marker=None, limit=None, sort_key='created_at',
              sort_dir='desc', filters=None):
        try:
            ns_repo = self.gateway.get_metadef_namespace_repo(req.context)

            # Get namespace id
            if marker:
                namespace_obj = ns_repo.get(marker)
                marker = namespace_obj.namespace_id

            database_ns_list = ns_repo.list(
                marker=marker, limit=limit, sort_key=sort_key,
                sort_dir=sort_dir, filters=filters)
            for db_namespace in database_ns_list:
                # Get resource type associations
                filters = dict()
                filters['namespace'] = db_namespace.namespace
                rs_repo = (
                    self.gateway.get_metadef_resource_type_repo(req.context))
                repo_rs_type_list = rs_repo.list(filters=filters)
                resource_type_list = [ResourceTypeAssociation.to_wsme_model(
                    resource_type) for resource_type in repo_rs_type_list]
                if resource_type_list:
                    db_namespace.resource_type_associations = (
                        resource_type_list)

            namespace_list = [Namespace.to_wsme_model(
                db_namespace,
                get_namespace_href(db_namespace),
                self.ns_schema_link) for db_namespace in database_ns_list]
            namespaces = Namespaces()
            namespaces.namespaces = namespace_list
            if len(namespace_list) != 0 and len(namespace_list) == limit:
                namespaces.next = namespace_list[-1].namespace

        except exception.Forbidden as e:
            LOG.debug("User not permitted to retrieve metadata namespaces "
                      "index")
            raise webob.exc.HTTPForbidden(explanation=e.msg)
        except exception.NotFound as e:
            raise webob.exc.HTTPNotFound(explanation=e.msg)
        except Exception as e:
            LOG.error(encodeutils.exception_to_unicode(e))
            raise webob.exc.HTTPInternalServerError()
        return namespaces
开发者ID:mahak,项目名称:glance,代码行数:45,代码来源:metadef_namespaces.py

示例4: create

    def create(self, req, resource_type, namespace):
        rs_type_factory = self.gateway.get_metadef_resource_type_factory(req.context)
        rs_type_repo = self.gateway.get_metadef_resource_type_repo(req.context)
        try:
            new_resource_type = rs_type_factory.new_resource_type(namespace=namespace, **resource_type.to_dict())
            rs_type_repo.add(new_resource_type)

        except exception.Forbidden as e:
            LOG.debug("User not permitted to create metadata resource type " "within '%s' namespace", namespace)
            raise webob.exc.HTTPForbidden(explanation=e.msg)
        except exception.NotFound as e:
            raise webob.exc.HTTPNotFound(explanation=e.msg)
        except exception.Duplicate as e:
            raise webob.exc.HTTPConflict(explanation=e.msg)
        except Exception as e:
            LOG.error(encodeutils.exception_to_unicode(e))
            raise webob.exc.HTTPInternalServerError()
        return ResourceTypeAssociation.to_wsme_model(new_resource_type)
开发者ID:bgxavier,项目名称:glance,代码行数:18,代码来源:metadef_resource_types.py

示例5: show

 def show(self, req, namespace):
     try:
         filters = {'namespace': namespace}
         rs_type_repo = self.gateway.get_metadef_resource_type_repo(
             req.context)
         db_resource_type_list = rs_type_repo.list(filters=filters)
         resource_type_list = [ResourceTypeAssociation.to_wsme_model(
             resource_type) for resource_type in db_resource_type_list]
         resource_types = ResourceTypeAssociations()
         resource_types.resource_type_associations = resource_type_list
     except exception.Forbidden as e:
         raise webob.exc.HTTPForbidden(explanation=e.msg)
     except exception.NotFound as e:
         raise webob.exc.HTTPNotFound(explanation=e.msg)
     except Exception as e:
         LOG.error(e)
         raise webob.exc.HTTPInternalServerError(e)
     return resource_types
开发者ID:HoratiusTang,项目名称:glance,代码行数:18,代码来源:test_metadef_resourcetypes.py

示例6: show

 def show(self, req, namespace):
     try:
         filters = {"namespace": namespace}
         rs_type_repo = self.gateway.get_metadef_resource_type_repo(req.context)
         db_resource_type_list = rs_type_repo.list(filters=filters)
         resource_type_list = [
             ResourceTypeAssociation.to_wsme_model(resource_type) for resource_type in db_resource_type_list
         ]
         resource_types = ResourceTypeAssociations()
         resource_types.resource_type_associations = resource_type_list
     except exception.Forbidden as e:
         LOG.debug("User not permitted to retrieve metadata resource types " "within '%s' namespace", namespace)
         raise webob.exc.HTTPForbidden(explanation=e.msg)
     except exception.NotFound as e:
         raise webob.exc.HTTPNotFound(explanation=e.msg)
     except Exception as e:
         LOG.error(encodeutils.exception_to_unicode(e))
         raise webob.exc.HTTPInternalServerError(e)
     return resource_types
开发者ID:bgxavier,项目名称:glance,代码行数:19,代码来源:metadef_resource_types.py

示例7: create

    def create(self, req, resource_type, namespace):
        rs_type_factory = self.gateway.get_metadef_resource_type_factory(req.context)
        rs_type_repo = self.gateway.get_metadef_resource_type_repo(req.context)
        try:
            new_resource_type = rs_type_factory.new_resource_type(namespace=namespace, **resource_type.to_dict())
            rs_type_repo.add(new_resource_type)

        except exception.Forbidden as e:
            msg = _LE("Forbidden to create resource type. Reason: %(" "reason)s") % {
                "reason": utils.exception_to_str(e)
            }
            LOG.error(msg)
            raise webob.exc.HTTPForbidden(explanation=e.msg)
        except exception.NotFound as e:
            raise webob.exc.HTTPNotFound(explanation=e.msg)
        except exception.Duplicate as e:
            raise webob.exc.HTTPConflict(explanation=e.msg)
        except Exception as e:
            LOG.error(e)
            raise webob.exc.HTTPInternalServerError()
        return ResourceTypeAssociation.to_wsme_model(new_resource_type)
开发者ID:ianunruh,项目名称:glance,代码行数:21,代码来源:test_metadef_resourcetypes.py


注:本文中的glance.api.v2.model.metadef_resource_type.ResourceTypeAssociation类示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。