本文整理汇总了Python中feedgen.feed.FeedGenerator.from_rss方法的典型用法代码示例。如果您正苦于以下问题：Python FeedGenerator.from_rss方法的具体用法？Python FeedGenerator.from_rss怎么用？Python FeedGenerator.from_rss使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类feedgen.feed.FeedGenerator的用法示例。
在下文中一共展示了FeedGenerator.from_rss方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: listen_for_urls
# 需要导入模块: from feedgen.feed import FeedGenerator [as 别名]
# 或者: from feedgen.feed.FeedGenerator import from_rss [as 别名]
def listen_for_urls(self, msg, match):
url = re.findall('http[s]?://(?:[a-zA-Z]|[0-9]|[[email protected]&+]|[!*\(\),]|(?:%[0-9a-fA-F][0-9a-fA-F]))+', str(msg))
p = re.compile('\/(.*)')
user = re.search(p, str(msg.getFrom())).group()[1:]
if len(url) == 1:
url = str(url[0])
filename = '/mnt/extern1/SYSTEM/www/foorss/' + user + '.xml'
fg = FeedGenerator()
# Some pages block urllib2 so we need a fake user agent
header = {'User-Agent': 'Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.11 (KHTML, like Gecko) Chrome/23.0.1271.64 Safari/537.11',
'Accept': 'text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8',
'Accept-Charset': 'ISO-8859-1,utf-8;q=0.7,*;q=0.3',
'Accept-Encoding': 'none',
'Accept-Language': 'en-US,en;q=0.8',
'Connection': 'keep-alive'}
req = urllib2.Request(url, headers=header)
try:
soup = BeautifulSoup(urllib2.urlopen(req))
except urllib2.HTTPError, e:
print e.fp.read()
yield "Error while parsing the website..."
if os.path.isfile(filename):
fg.from_rss(filename)
else:
fg.id(user)
fg.title('Some Testfeed')
fg.link( href='http://nix.da', rel='alternate' )
fg.description('This is a cool feed!')
if soup.title != None:
title = soup.title.string
else:
title = url
fe = fg.add_entry()
fe.id(url)
fe.title(title)
fe.description('Description')
fe.link([{'href': url}])
fg.rss_file(filename)
yield title + ' from ' + user + ' (rss updated)'