本文整理汇总了Python中emcee.utils.MPIPool.bcast方法的典型用法代码示例。如果您正苦于以下问题：Python MPIPool.bcast方法的具体用法？Python MPIPool.bcast怎么用？Python MPIPool.bcast使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类emcee.utils.MPIPool的用法示例。
在下文中一共展示了MPIPool.bcast方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: range
# 需要导入模块: from emcee.utils import MPIPool [as 别名]
# 或者: from emcee.utils.MPIPool import bcast [as 别名]
bnds = np.zeros(3*(ndish-1), dtype=beta0.dtype) # as bounds of values
for i in range(ndish-1): # for center_dish == 15 only
bnds[3*i:3*(i+1)] = bnd
else:
x0 = np.zeros(3*(ndish-1)+3*num_nf, dtype=beta0.dtype)
x0[:3*center_dish] = beta0[:3*center_dish]
x0[3*center_dish:] = beta0[3*(center_dish+1):]
x1 = np.zeros(3*(ndish-1)+3*num_nf, dtype=beta1.dtype)
x1[:3*center_dish] = beta1[:3*center_dish]
x1[3*center_dish:] = beta1[3*(center_dish+1):]
bnds = np.zeros(3*(ndish-1)+3*num_nf, dtype=beta0.dtype)
for i in range(ndish-1): # for center_dish == 15 only
bnds[3*i:3*(i+1)] = bnd
bnds[-3*num_nf:] = r
Phi = pool.bcast(Phi, root=0)
x0 = pool.bcast(x0, root=0)
x1 = pool.bcast(x1, root=0)
beta0 = pool.bcast(beta0, root=0)
beta1 = pool.bcast(beta1, root=0)
bnds = pool.bcast(bnds, root=0)
ndiff = num_nf * (num_nf - 1) / 2
diff_Phi = np.zeros((ndiff, npol, nbl), dtype=Phi.dtype)
diff_inds = [(i, j) for i in range(num_nf) for j in range(i+1, num_nf)]
for ind, (i, j) in enumerate(diff_inds):
diff_Phi[ind] = Phi[j] - Phi[i]
diff_Phi = np.mod(diff_Phi, 2*np.pi)
def chi2(x):