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Python ModelBackend.has_perm方法代码示例

本文整理汇总了Python中django.contrib.auth.backends.ModelBackend.has_perm方法的典型用法代码示例。如果您正苦于以下问题:Python ModelBackend.has_perm方法的具体用法?Python ModelBackend.has_perm怎么用?Python ModelBackend.has_perm使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在django.contrib.auth.backends.ModelBackend的用法示例。


在下文中一共展示了ModelBackend.has_perm方法的4个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Python代码示例。

示例1: ElectionAuthBackend

# 需要导入模块: from django.contrib.auth.backends import ModelBackend [as 别名]
# 或者: from django.contrib.auth.backends.ModelBackend import has_perm [as 别名]
class ElectionAuthBackend(object):
    """
    Authenticate against django.contrib.auth.backends.ModelBackend AND ipauth.backend.RangeBackend
    Users must pass both sets of authentication to use the system
    """
    supports_anonymous_user = False
    ipauth_backend = None
    model_backend = None

    def __init__(self):
        self.ipauth_backend = RangeBackend()
        self.model_backend = ModelBackend()
    
    def authenticate(self, username=None, password=None, ip=None):
        """
        Authenticate against multiple backends AND'd together
        TODO: Election admin
        """
        model_user = self.model_backend.authenticate(username=username, password=password)
        ip_user = self.ipauth_backend.authenticate(ip=ip)        
        #print 'model_user', repr(model_user)
        #print 'model_user groups', repr(model_user.groups.all())
        #print 'ip_user', repr(ip_user)
        admin_group = Group.objects.filter(name='ADMIN').all()
        if admin_group.count() > 0:
          admin_group = admin_group[0]
        else:
          admin_group = None

        if not model_user:
            return None
        if model_user.is_superuser or model_user.is_staff: # Super admin
            return model_user
        if model_user.groups.count() > 0 and admin_group in model_user.groups.all(): # Election admin
            return model_user
        #if ip_user is None:
            #print 'Your IP=%s is not in the IPAuth' % (ip, )
            #return None
        return model_user

    def get_group_permissions(self, user_obj):
        """
        Returns a set of permission strings that this user has through his/her
        groups.
        """
        return self.model_backend.get_group_permissions(user_obj)

    def get_all_permissions(self, user_obj):
        return self.model_backend.get_all_permissions(user_obj)

    def has_perm(self, user_obj, perm):
        return self.model_backend.has_perm(user_obj, perm)

    def has_module_perms(self, user_obj, app_label):
        return self.model_backend.has_module_perms(user_obj, app_label)

    def get_user(self, user_id):
        return self.model_backend.get_user(user_id)
开发者ID:Hwesta,项目名称:bc-stv-voting-system,代码行数:60,代码来源:backend.py

示例2: has_perm

# 需要导入模块: from django.contrib.auth.backends import ModelBackend [as 别名]
# 或者: from django.contrib.auth.backends.ModelBackend import has_perm [as 别名]
 def has_perm(self, user_obj, perm, obj=None):
     if obj is None:
         # fallback to Django default permission backend
         return ModelBackend.has_perm(self, user_obj, perm)
     else:
         # in case the user is the owner, he/she has always permissions, 
         # otherwise we need to check
         if hasattr(obj, 'owner') and user_obj == obj.owner:
             return True
         else:
             return perm in self.get_all_permissions(user_obj, obj=obj)
开发者ID:HABIYAREMYE,项目名称:geonode,代码行数:13,代码来源:auth.py

示例3: has_permission

# 需要导入模块: from django.contrib.auth.backends import ModelBackend [as 别名]
# 或者: from django.contrib.auth.backends.ModelBackend import has_perm [as 别名]
def has_permission(user, permission_codename, obj=None, canedit = False):
    from djpcms.models import Page, BlockContent, ObjectPermission
    if not obj:
        back = ModelBackend()
        if permission_codename[-4:] == 'view':
            return True
        if not user.is_active:
            return False
        if user.is_superuser:
            return True
        return back.has_perm(user, permission_codename)
    else:
        anony = user.is_anonymous()
        opts = obj._meta
        
        viewperm     = get_view_permission(obj) == permission_codename
        changeperm   = opts.app_label + '.' + opts.get_change_permission() == permission_codename
        
        # Do Page and BlockContent first
        if isinstance(obj,Page):
            if anony and obj.requires_login:
                return False
            if changeperm and obj.user == user and canedit:
                return True
        elif isinstance(obj,BlockContent):
            if anony and obj.requires_login:
                return False
            if changeperm and obj.page.user == user and canedit:
                return True
            if viewperm and not anony and obj.for_not_authenticated:
                return False
        
        if user.is_superuser:
            return True
        
        perms = ObjectPermission.objects.for_object(obj, permission_codename)
        if perms:
            for perm in perms:
                if perm.has_perm(user):
                    return True
            return False
        
        # Fall back to permission without object
        return has_permission(user, permission_codename)
开发者ID:strogo,项目名称:djpcms,代码行数:46,代码来源:permissions.py

示例4: has_perm

# 需要导入模块: from django.contrib.auth.backends import ModelBackend [as 别名]
# 或者: from django.contrib.auth.backends.ModelBackend import has_perm [as 别名]
    def has_perm(self, user_obj, perm, obj=None):
        """
        It is assumed that perm will be one of the Django default perm codes
        like 'delete_comment' or 'change_comment'.  The default users, however,
        will not have the default privileges for the delete and change verbs.
        Instead, they will have '_own' versions of the verbs:
        'change_comment_own', 'delete_comment_own'

        The first step is to call has_perm w/o the object to use standard
        permission checking (do this on purpose).  If the user has the
        permission, return True.
        """
        # print "ModelBackendPlus.has_perm()"

        allowed = ModelBackend.has_perm(self, user_obj, perm)
        if allowed:
            return True

        # The majority of users will fail this check because only non-default
        # auth_groups will have any of the default permissions for the create
        # and delete verbs
        #
        # If an obj is not None, however, we have the chance to check the
        # business rule for the "_own" extension of the perm verb, namely, that
        # the object was created by the user.
        #
        # The idea is that in a conventional RBAC scheme, we would always have
        # a task, i.e., "read" as the lowest child and it would have a parent
        # "read_own" that would need a business rule of "the session user
        # created this model"
        #
        # All of the "_own" permissions verbs would be put into the default
        # auth_group

        if obj is not None:

            # print "ModelBackendPlus.has_perm() obj is not None"

            # Make sure obj has a user property.  If it does not, return
            # False.  Again, we will call ModelBackend.has_perm without the
            # object parameter so that we bypass the built-in object workflow,
            # which is incomplete

            if hasattr(obj, "user"):

                #print "ModelBackendPlus.has_perm() obj has user property"

                # DEBUG
                #a = ModelBackend.has_perm(self, user_obj, perm + '_own')
                #b = obj.user == user_obj
                #
                #print "ModelBackendPlus.has_perm() _own:" + \
                #      "true" if a else "false"
                #print "ModelBackendPlus.has_perm() obj.user = user: " + \
                #      "true" if b else "false"

                return (ModelBackend.has_perm(self, user_obj, perm + '_own') and
                        obj.user == user_obj)
            else:
                return False
        else:
            return False
开发者ID:cnanders,项目名称:test-cxro-tickets,代码行数:64,代码来源:backends.py


注:本文中的django.contrib.auth.backends.ModelBackend.has_perm方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。