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Python Decoder.append方法代码示例

本文整理汇总了Python中decoder.Decoder.append方法的典型用法代码示例。如果您正苦于以下问题:Python Decoder.append方法的具体用法?Python Decoder.append怎么用?Python Decoder.append使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在decoder.Decoder的用法示例。


在下文中一共展示了Decoder.append方法的2个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Python代码示例。

示例1: encode_decode

# 需要导入模块: from decoder import Decoder [as 别名]
# 或者: from decoder.Decoder import append [as 别名]
    def encode_decode(self, k):

        print "\nTesting encoding and then decoding with k = %s" % k

        md5 = hashlib.md5()

        with FileChunker(k, SYMBOLSIZE, DEFAULT_FILE) as chunker:
            chunk = chunker.chunk()
            while chunk:
                padding = chunk.padding

                symbols = [(i, chunk[i]) for i in xrange(k)]
                encoder = Encoder(k, symbols)
                symbols = []

                # Start at k/2 and produce 1.25k more symbols to get a mix
                # of parity and source symbols
                for i in xrange(k * 2):
                    symbols.append(encoder.next())

                encoder = None
                decoder = Decoder(k)
                for tup in symbols:
                    decoder.append(tup)

                decoder.decode()
                decoded = bytearray()
                for i in xrange(k):
                    esi, s = decoder.next()
                    decoded += s.tostring()
                decoder = None

                if padding:
                    padding = 0 - padding
                    print "Removing padding", padding, "bytes"
                    decoded = decoded[:padding]

                md5.update(decoded)
                # Continue on to the next chunk
                chunk = chunker.chunk()

        print "Original digest:", self.original_digest
        print "Decoded digest:", md5.hexdigest()
        return self.original_digest == md5.hexdigest()
开发者ID:absalon-james,项目名称:velopyraptor,代码行数:46,代码来源:test_encoding_decoding.py

示例2: decode

# 需要导入模块: from decoder import Decoder [as 别名]
# 或者: from decoder.Decoder import append [as 别名]
    def decode(self):
        """
        Orchestrates the reading of file shares into encoded symbols
        and decoding of the encoded symbols
        """
        self.stats['start_time'] = time.time()

        self.verify_input_dir()
        self.verify_output_file()

        # Outer loop will iterate over blocks in a directory.
        # Block directories contain shares per block.
        # Blocks start at 0 and increment by 1.  If block n doesn't exist
        # Then assume that is the end of the file
        block = 0
        blockdir = os.path.join(self.input_dir, str(block))
        while os.path.exists(blockdir):

            # Attempt to read metadata for this block
            self.start_timer()
            k, padding = self.read_block_meta_data(blockdir)
            self.add_time(self.stop_timer(), 'io_time')

            # For each file in the block directory(excluding meta) read each
            # share.  Each will be an encoding symbol

            decoder = Decoder(k)
            read_symbols = 0

            for _file in os.listdir(blockdir):
                # Skip non files
                if not os.path.isfile(os.path.join(blockdir, _file)):
                    continue

                try:
                    # Open the share file in binary mode
                    self.start_timer()

                    symbol = numpy.fromfile(os.path.join(blockdir, _file),
                                            dtype='uint64')
                    self.add_time(self.stop_timer(), 'io_time')

                    # Add the symbol to the decoder.
                    # A symbol is a (integer, numpy array) tuple
                    can_decode = decoder.append((int(_file), symbol))
                    read_symbols += 1
                    if can_decode:
                        break
                except Exception:
                    continue
                    pass

            # Ideally we want more than k encoded symbols.
            # We will fail with less than k
            if read_symbols < k:
                self.exit("There were not sufficient symbols"
                          " to recover block %s" % block)

            if not can_decode:
                self.exit("A decoding schedule was not possible "
                          "with the symbols provided.")

            # Instruct decoder to calculate intermediate symbols from
            # known encoding symbols
            self.start_timer()
            decoder.decode()
            self.add_time(self.stop_timer(), 'decoding_time')

            # Steam source symbol output by encoding the first
            # k encoded symbols.
            # The first k source symbols == the first k encoding symbols
            target = open(self.output_file, 'ab')
            for i in xrange(k):

                self.start_timer()
                s = decoder.next()[1]
                self.add_time(self.stop_timer(), 'decoding_time')

                self.start_timer()
                s.tofile(target)
                self.add_time(self.stop_timer(), 'io_time')
            target.close()

            # Padding should only be on the last block but we check anyway
            # @TODO - Ensure file size is accurate before truncating
            if (padding):
                self.start_timer()
                size = os.path.getsize(self.output_file) - padding
                target = io.open(self.output_file, 'a+b')
                target.truncate(size)
                target.close()
                self.add_time(self.stop_timer(), 'io_time')

            # Increment block number by 1
            block += 1
            blockdir = os.path.join(self.input_dir, str(block))

        self.stats['blocks_decoded'] = block
        self.stats['end_time'] = time.time()
        self.stats['elapsed_time'] = \
#.........这里部分代码省略.........
开发者ID:absalon-james,项目名称:velopyraptor,代码行数:103,代码来源:file_decoder.py


注:本文中的decoder.Decoder.append方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。