本文整理汇总了Python中bt.core.StrategyBase.allocate方法的典型用法代码示例。如果您正苦于以下问题：Python StrategyBase.allocate方法的具体用法？Python StrategyBase.allocate怎么用？Python StrategyBase.allocate使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类bt.core.StrategyBase的用法示例。
在下文中一共展示了StrategyBase.allocate方法的6个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: test_strategybase_flatten
# 需要导入模块: from bt.core import StrategyBase [as 别名]
# 或者: from bt.core.StrategyBase import allocate [as 别名]
def test_strategybase_flatten():
s = StrategyBase('s')
dts = pd.date_range('2010-01-01', periods=3)
data = pd.DataFrame(index=dts, columns=['c1', 'c2'], data=100)
s.setup(data)
i = 0
s.update(dts[i])
s.adjust(1000)
s.allocate(100, 'c1')
c1 = s['c1']
s.allocate(100, 'c2')
c2 = s['c2']
assert c1.position == 1
assert c1.value == 100
assert c2.position == 1
assert c2.value == 100
assert s.value == 998
s.flatten()
assert c1.position == 0
assert c1.value == 0
assert s.value == 996示例2: test_strategybase_tree_allocate_child_from_strategy
# 需要导入模块: from bt.core import StrategyBase [as 别名]
# 或者: from bt.core.StrategyBase import allocate [as 别名]
def test_strategybase_tree_allocate_child_from_strategy():
c1 = SecurityBase('c1')
c2 = SecurityBase('c2')
s = StrategyBase('p', [c1, c2])
c1 = s['c1']
c2 = s['c2']
dts = pd.date_range('2010-01-01', periods=3)
data = pd.DataFrame(index=dts, columns=['c1', 'c2'], data=100)
data['c1'][dts[1]] = 105
data['c2'][dts[1]] = 95
s.setup(data)
i = 0
s.update(dts[i], data.ix[dts[i]])
s.adjust(1000)
# since children have w == 0 this should stay in s
s.allocate(1000)
assert s.value == 1000
assert s.capital == 1000
assert c1.value == 0
assert c2.value == 0
# now allocate to c1
s.allocate(500, 'c1')
assert c1.position == 5
assert c1.value == 500
assert s.capital == 1000 - 501
assert s.value == 999
assert c1.weight == 500.0 / 999
assert c2.weight == 0示例3: test_strategybase_tree_allocate_level2
# 需要导入模块: from bt.core import StrategyBase [as 别名]
# 或者: from bt.core.StrategyBase import allocate [as 别名]
def test_strategybase_tree_allocate_level2():
c1 = SecurityBase('c1')
c12 = copy.deepcopy(c1)
c2 = SecurityBase('c2')
c22 = copy.deepcopy(c2)
s1 = StrategyBase('s1', [c1, c2])
s2 = StrategyBase('s2', [c12, c22])
m = StrategyBase('m', [s1, s2])
dts = pd.date_range('2010-01-01', periods=3)
data = pd.DataFrame(index=dts, columns=['c1', 'c2'], data=100)
data['c1'][dts[1]] = 105
data['c2'][dts[1]] = 95
m.setup(data)
i = 0
m.update(dts[i], data.ix[dts[i]])
m.adjust(1000)
# since children have w == 0 this should stay in s
m.allocate(1000)
assert m.value == 1000
assert m.capital == 1000
assert s1.value == 0
assert s2.value == 0
assert c1.value == 0
assert c2.value == 0
# now allocate directly to child
s1.allocate(500)
assert s1.value == 500
assert m.capital == 1000 - 500
assert m.value == 1000
assert s1.weight == 500.0 / 1000
assert s2.weight == 0
# now allocate directly to child of child
c1.allocate(200)
assert s1.value == 499
assert s1.capital == 500 - 201
assert c1.value == 200
assert c1.weight == 200.0 / 499
assert c1.position == 2
assert m.capital == 1000 - 500
assert m.value == 999
assert s1.weight == 499.0 / 999
assert s2.weight == 0
assert c12.value == 0示例4: test_strategybase_prices
# 需要导入模块: from bt.core import StrategyBase [as 别名]
# 或者: from bt.core.StrategyBase import allocate [as 别名]
def test_strategybase_prices():
dts = pd.date_range('2010-01-01', periods=21)
rawd = [13.555, 13.75, 14.16, 13.915, 13.655,
13.765, 14.02, 13.465, 13.32, 14.65,
14.59, 14.175, 13.865, 13.865, 13.89,
13.85, 13.565, 13.47, 13.225, 13.385,
12.89]
data = pd.DataFrame(index=dts, data=rawd, columns=['a'])
s = StrategyBase('s')
s.setup(data)
# buy 100 shares on day 1 - hold until end
# just enough to buy 100 shares + 1$ commission
s.adjust(1356.50)
s.update(dts[0])
# allocate all capital to child a
# a should be dynamically created and should have
# 100 shares allocated. s.capital should be 0
s.allocate(s.value, 'a')
assert s.capital == 0
assert s.value == 1355.50
assert len(s.children) == 1
aae(s.price, 99.92628, 5)
a = s['a']
assert a.position == 100
assert a.value == 1355.50
assert a.weight == 1
assert a.price == 13.555
assert len(a.prices) == 1
# update through all dates and make sure price is ok
s.update(dts[1])
aae(s.price, 101.3638, 4)
s.update(dts[2])
aae(s.price, 104.3863, 4)
s.update(dts[3])
aae(s.price, 102.5802, 4)
# finish updates and make sure ok at end
for i in range(4, 21):
s.update(dts[i])
assert len(s.prices) == 21
aae(s.prices[-1], 95.02396, 5)
aae(s.prices[-2], 98.67306, 5)示例5: test_set_commissions
# 需要导入模块: from bt.core import StrategyBase [as 别名]
# 或者: from bt.core.StrategyBase import allocate [as 别名]
def test_set_commissions():
s = StrategyBase('s')
dts = pd.date_range('2010-01-01', periods=3)
data = pd.DataFrame(index=dts, columns=['c1', 'c2'], data=100)
s.setup(data)
s.update(dts[0])
s.adjust(1000)
s.allocate(500, 'c1')
assert s.capital == 499
s.set_commissions(lambda x, y: 0.0)
s.allocate(-500, 'c1')
assert s.capital == 999示例6: test_strategy_tree_proper_return_calcs
# 需要导入模块: from bt.core import StrategyBase [as 别名]
# 或者: from bt.core.StrategyBase import allocate [as 别名]
def test_strategy_tree_proper_return_calcs():
s1 = StrategyBase('s1')
s2 = StrategyBase('s2')
m = StrategyBase('m', [s1, s2])
s1 = m['s1']
s2 = m['s2']
dts = pd.date_range('2010-01-01', periods=3)
data = pd.DataFrame(index=dts, columns=['c1', 'c2'], data=100)
data.loc['c1', dts[1]] = 105
data.loc['c2', dts[1]] = 95
m.setup(data)
i = 0
m.update(dts[i], data.ix[dts[i]])
m.adjust(1000)
# since children have w == 0 this should stay in s
m.allocate(1000)
assert m.value == 1000
assert m.capital == 1000
assert m.price == 100
assert s1.value == 0
assert s2.value == 0
# now allocate directly to child
s1.allocate(500)
assert m.capital == 500
assert m.value == 1000
assert m.price == 100
assert s1.value == 500
assert s1.weight == 500.0 / 1000
assert s1.price == 100
assert s2.weight == 0
# allocate to child2 via master method
m.allocate(500, 's2')
assert m.capital == 0
assert m.value == 1000
assert m.price == 100
assert s1.value == 500
assert s1.weight == 500.0 / 1000
assert s1.price == 100
assert s2.value == 500
assert s2.weight == 500.0 / 1000
assert s2.price == 100
# now allocate and incur commission fee
s1.allocate(500, 'c1')
assert m.capital == 0
assert m.value == 999
assert m.price == 99.9
assert s1.value == 499
assert s1.weight == 499.0 / 999.0
assert s1.price == 99.8
assert s2.value == 500
assert s2.weight == 500.0 / 999.0
assert s2.price == 100