本文整理汇总了Python中apps.web.bundles.BundleService.read_target方法的典型用法代码示例。如果您正苦于以下问题:Python BundleService.read_target方法的具体用法?Python BundleService.read_target怎么用?Python BundleService.read_target使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类apps.web.bundles.BundleService
的用法示例。
在下文中一共展示了BundleService.read_target方法的2个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: BundleDownload
# 需要导入模块: from apps.web.bundles import BundleService [as 别名]
# 或者: from apps.web.bundles.BundleService import read_target [as 别名]
def BundleDownload(request, uuid):
"""
Return a stream with the contents of the bundle (zip file if necessary).
This is the same code as BundleFileContentApi.
"""
service = BundleService(request.user)
stream, name, content_type = service.read_target((uuid, ""))
response = StreamingHttpResponse(stream, content_type=content_type)
response["Content-Disposition"] = 'filename="%s"' % name
return response
示例2: get
# 需要导入模块: from apps.web.bundles import BundleService [as 别名]
# 或者: from apps.web.bundles.BundleService import read_target [as 别名]
def get(self, request, uuid, path):
service = BundleService(self.request.user)
try:
stream, name, content_type = service.read_target((uuid, path))
response = StreamingHttpResponse(stream, content_type=content_type)
response['Content-Disposition'] = 'filename="%s"' % name
return response
except Exception as e:
tb = traceback.format_exc()
log_exception(self, e, tb)
return Response({"error": smart_str(e)}, status=500)