本文整理汇总了Python中app.users.models.User.is_following方法的典型用法代码示例。如果您正苦于以下问题：Python User.is_following方法的具体用法？Python User.is_following怎么用？Python User.is_following使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类app.users.models.User的用法示例。
在下文中一共展示了User.is_following方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: test_follow
# 需要导入模块: from app.users.models import User [as 别名]
# 或者: from app.users.models.User import is_following [as 别名]
def test_follow(self):
user1 = User(name='mark', email='[email protected]')
user2 = User(name='rudy', email='[email protected]')
db.session.add(user1)
db.session.add(user2)
db.session.commit()
self.assertEqual(user1.is_following(user2), False)
self.assertEqual(user1.unfollow(user2), None)
user1 = user1.follow(user2)
db.session.add(user1)
db.session.commit()
# user1 has already followed user2
self.assertEqual(user1.follow(user2), None)
self.assertEqual(user1.followed.count(), 1)
self.assertEqual(user1.followed.first().name, 'rudy')
self.assertEqual(user2.followers.count(), 1)
self.assertEqual(user2.followers.first().name, 'mark')
user1 = user1.unfollow(user2)
db.session.add(user1)
db.session.commit()
self.assertEqual(user1.unfollow(user2), None)
self.assertEqual(user1.is_following(user2), False)
self.assertEqual(user1.followed.count(), 0)
self.assertEqual(user2.followers.count(), 0)