本文整理汇总了Python中admit.util.AdmitLogging.AdmitLogging.getEffectiveLevel方法的典型用法代码示例。如果您正苦于以下问题:Python AdmitLogging.getEffectiveLevel方法的具体用法?Python AdmitLogging.getEffectiveLevel怎么用?Python AdmitLogging.getEffectiveLevel使用的例子?那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类admit.util.AdmitLogging.AdmitLogging
的用法示例。
在下文中一共展示了AdmitLogging.getEffectiveLevel方法的1个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: test_effectiveLevel
# 需要导入模块: from admit.util.AdmitLogging import AdmitLogging [as 别名]
# 或者: from admit.util.AdmitLogging.AdmitLogging import getEffectiveLevel [as 别名]
def test_effectiveLevel(self):
msg = "unit_test_levels_message"
# check that the logging level is what is expected
level = Alogging.getEffectiveLevel()
self.assertTrue(level == self.level)
# set the level to a new value and check again
Alogging.setLevel(50)
level = Alogging.getEffectiveLevel()
self.assertTrue(level == 50)
# log an info message which is below the logging level, this message should not appear
# in the logs
Alogging.info(msg)
found = False
r = open(self.logfile, 'r')
for line in r.readlines():
if msg in line:
if(self.verbose):
print "\nFound message >", line
found = True
break
r.close()
self.assertFalse(found)
Alogging.setLevel(self.level)
# reset the logging level
msg += "2"
# log an info message, which is now above the logging level, this message should appear
# in the logs
Alogging.info(msg)
found = False
r = open(self.logfile, 'r')
for line in r.readlines():
if msg in line:
if(self.verbose):
print "\nFound message >", line
found = True
r.close()
break
self.assertTrue(found)