本文整理汇总了Python中Solver.Solver.solve_bloch_Brillouin方法的典型用法代码示例。如果您正苦于以下问题：Python Solver.solve_bloch_Brillouin方法的具体用法？Python Solver.solve_bloch_Brillouin怎么用？Python Solver.solve_bloch_Brillouin使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类Solver.Solver的用法示例。
在下文中一共展示了Solver.solve_bloch_Brillouin方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: write_solver_input
# 需要导入模块: from Solver import Solver [as 别名]
# 或者: from Solver.Solver import solve_bloch_Brillouin [as 别名]
import matplotlib.pyplot as plt
from matplotlib import rc
filename = 'unit_cell_1-02_two_reg'
write_solver_input(filename +'.msh',dimension = 2, bc_type = 'Bloch', \
parameter = [], eq = 'EM', sol_type = 'Stationary',analysis_param \
= ['y', 'y', 15, 15, 21, 21, 5], bc_filename = filename +'_guide.bc')
simu = Simulation()
simu.read_solver_input(filename +'.msh')
simu.domain.read_mesh_file(filename +'.msh',simu)
inter = Interpreter(vectorial = True)
eq = inter.build_EM_bloch_eq(simu)
my_solver = Solver()
k_coords, energy = my_solver.solve_bloch_Brillouin(simu, eq)
fig = plt.figure()
ax = fig.add_subplot(111)
plt.title("Dispersion relations for Square lattice")
k_div = k_coords.shape[0]/3
from numpy import sqrt, around
print max(energy[:,-1])
for i in range(energy.shape[1]):
energy[:,i] = sqrt(around(energy[:,i],10))
ax.plot(energy[:,i])
l = plt.axvline(x=k_div)
l = plt.axvline(x=k_div*2+1)
l = plt.axvline(x= k_coords.shape[0])
plt.ylim(0, max(energy[:,-1]))