本文整理汇总了Python中PyQt5.QtWebKitWidgets.QWebPage.acceptNavigationRequest方法的典型用法代码示例。如果您正苦于以下问题：Python QWebPage.acceptNavigationRequest方法的具体用法？Python QWebPage.acceptNavigationRequest怎么用？Python QWebPage.acceptNavigationRequest使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类PyQt5.QtWebKitWidgets.QWebPage的用法示例。
在下文中一共展示了QWebPage.acceptNavigationRequest方法的3个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: acceptNavigationRequest
# 需要导入模块: from PyQt5.QtWebKitWidgets import QWebPage [as 别名]
# 或者: from PyQt5.QtWebKitWidgets.QWebPage import acceptNavigationRequest [as 别名]
def acceptNavigationRequest(self, frame, request, type):
if(type == QWebPage.NavigationTypeLinkClicked):
if(frame == self.mainFrame()):
self.view().link_clicked(request.url())
else:
call_method("open-url", [request.url().toString()])
return False
return QWebPage.acceptNavigationRequest(self, frame, request, type) 示例2: acceptNavigationRequest
# 需要导入模块: from PyQt5.QtWebKitWidgets import QWebPage [as 别名]
# 或者: from PyQt5.QtWebKitWidgets.QWebPage import acceptNavigationRequest [as 别名]
def acceptNavigationRequest(self, frame, request, type):
if(type == QWebPage.NavigationTypeLinkClicked):
url = request.url().toString()
if(frame == self.mainFrame()):
self.view().load(url)
return False
elif frame == None:
# self.createWindow(QWebPage.WebBrowserWindow, url)
webbrowser.open(request.url().toString())
return False
return QWebPage.acceptNavigationRequest(self, frame, request, type)示例3: acceptNavigationRequest
# 需要导入模块: from PyQt5.QtWebKitWidgets import QWebPage [as 别名]
# 或者: from PyQt5.QtWebKitWidgets.QWebPage import acceptNavigationRequest [as 别名]
def acceptNavigationRequest(self, frame, request, type):
# Handle myself if got user event.
if type == QWebPage.NavigationTypeLinkClicked:
if self.view().press_ctrl_flag:
call_method("open-url", [request.url().toString()])
else:
self.view().load(request.url())
# Return False to stop default behavior.
return False
# Otherwise, use default behavior.
return QWebPage.acceptNavigationRequest(self, frame, request, type)