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Python QMenu.insertAction方法代码示例

本文整理汇总了Python中PyQt4.QtGui.QMenu.insertAction方法的典型用法代码示例。如果您正苦于以下问题:Python QMenu.insertAction方法的具体用法?Python QMenu.insertAction怎么用?Python QMenu.insertAction使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在PyQt4.QtGui.QMenu的用法示例。


在下文中一共展示了QMenu.insertAction方法的1个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Python代码示例。

示例1: registerAction

# 需要导入模块: from PyQt4.QtGui import QMenu [as 别名]
# 或者: from PyQt4.QtGui.QMenu import insertAction [as 别名]
    def registerAction(self, action, menuName, callback=None):
        """ register an action to the manager's main menu """
        if not hasattr(self, '_registeredDbActions'):
            self._registeredDbActions = {}

        if callback is not None:
            invoke_callback = lambda x: self.invokeCallback(callback)

        if menuName is None or menuName == "":
            self.addAction(action)

            if menuName not in self._registeredDbActions:
                self._registeredDbActions[menuName] = list()
            self._registeredDbActions[menuName].append(action)

            if callback is not None:
                QObject.connect(action, SIGNAL("triggered(bool)"), invoke_callback)
            return True

        # search for the menu
        actionMenu = None
        helpMenuAction = None
        for a in self.menuBar.actions():
            if not a.menu() or a.menu().title() != menuName:
                continue
            if a.menu() != self.menuHelp:
                helpMenuAction = a

            actionMenu = a
            break

        # not found, add a new menu before the help menu
        if actionMenu is None:
            menu = QMenu(menuName, self)
            if helpMenuAction is not None:
                actionMenu = self.menuBar.insertMenu(helpMenuAction, menu)
            else:
                actionMenu = self.menuBar.addMenu(menu)

        menu = actionMenu.menu()
        menuActions = menu.actions()

        # get the placeholder's position to insert before it
        pos = 0
        for pos in range(len(menuActions)):
            if menuActions[pos].isSeparator() and menuActions[pos].objectName().endswith("_placeholder"):
                menuActions[pos].setVisible(True)
                break

        if pos < len(menuActions):
            before = menuActions[pos]
            menu.insertAction(before, action)
        else:
            menu.addAction(action)

        actionMenu.setVisible(True)  # show the menu

        if menuName not in self._registeredDbActions:
            self._registeredDbActions[menuName] = list()
        self._registeredDbActions[menuName].append(action)

        if callback is not None:
            QObject.connect(action, SIGNAL("triggered(bool)"), invoke_callback)

        return True
开发者ID:jarped,项目名称:QGIS,代码行数:67,代码来源:db_manager.py


注:本文中的PyQt4.QtGui.QMenu.insertAction方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。