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Python QLineF.dx方法代码示例

本文整理汇总了Python中PyQt4.QtCore.QLineF.dx方法的典型用法代码示例。如果您正苦于以下问题:Python QLineF.dx方法的具体用法?Python QLineF.dx怎么用?Python QLineF.dx使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在PyQt4.QtCore.QLineF的用法示例。


在下文中一共展示了QLineF.dx方法的1个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Python代码示例。

示例1: crop_line

# 需要导入模块: from PyQt4.QtCore import QLineF [as 别名]
# 或者: from PyQt4.QtCore.QLineF import dx [as 别名]
 def crop_line(self, line, line_point):
     global_rect = self.globalBoundingRect()
     
     # Go to local coordinate system - ellipse equations assume ellipse is centered on (0,0)        
     local_trans = global_rect.center()
     local_line = QLineF(line.p1() - local_trans, line.p2() - local_trans)
     
     if(local_line.dx() == 0):
         return line
     
     # Solve line equation        
     e_a = ((local_line.p2().y() - local_line.p1().y()) / 
               (local_line.p2().x() - local_line.p1().x()))
     
     e_b = local_line.p1().y() - e_a * local_line.p1().x()
     
     # ellipse params 
     e_c = global_rect.width()/2
     e_d = global_rect.height()/2
     
     # check condition
     if(e_c * e_d == 0):
         return line
     
     # precalculate things that are used more than once
     # a^2, b^2 ...
     ak = math.pow(e_a, 2)
     bk = math.pow(e_b, 2)
     ck = math.pow(e_c, 2)
     dk = math.pow(e_d, 2)
     
     # check another condition
     if((ak * ck + dk) == 0):
         return line
     
     # a^2*c^2, c^2*d^2
     akck = ak * ck
     ckdk = ck * dk
     
     # a*b*c^2
     abck = e_a*e_b*ck
     
     # parts of denomiator and numerator of x
     denom = (akck + dk)
     numer =  math.sqrt(ck*dk*(akck-bk+dk))
     
     # Decide which points to take
     xrel = (line.p1().x() > line.p2().x())
     yrel = (line.p1().y() > line.p2().y())
     
     if(line_point != 0):
         xrel = not xrel
         yrel = not yrel
     
     if((xrel and yrel) or (xrel and not yrel)):
         x1 = (-numer - abck) / denom
         y1 = (e_b*dk - e_a*math.sqrt(-ckdk*(-akck+bk-dk))) / denom
         
         intersectionPoint = QPointF(x1, y1)
     elif((not xrel and yrel) or (not xrel and not yrel)):
         x2 = (numer - abck) / denom         
         y2 = -(e_b*dk - e_a*math.sqrt(-ckdk*(-akck+bk-dk))) / denom  
     
         intersectionPoint = QPointF(x2, y2)
 
     # Go back to global coordinate system
     intersectionPoint = intersectionPoint + local_trans
 
     if(line_point == 0):
         return QLineF(intersectionPoint, line.p2())
     else:
         return QLineF(line.p1(), intersectionPoint)  
     
     return line
开发者ID:barnaba,项目名称:omelette,代码行数:76,代码来源:usecase.py


注:本文中的PyQt4.QtCore.QLineF.dx方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。