本文整理汇总了Python中LTTL.Segmenter.bypass方法的典型用法代码示例。如果您正苦于以下问题：Python Segmenter.bypass方法的具体用法？Python Segmenter.bypass怎么用？Python Segmenter.bypass使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类LTTL.Segmenter的用法示例。
在下文中一共展示了Segmenter.bypass方法的3个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: test_bypass_copy_annotations
# 需要导入模块: from LTTL import Segmenter [as 别名]
# 或者: from LTTL.Segmenter import bypass [as 别名]
def test_bypass_copy_annotations(self):
"""Does bypass copy annotations?"""
segmentation = Segmenter.bypass(self.other_letter_seg)
self.assertEqual(
[s.annotations['a'] for s in segmentation],
[s.annotations['a'] for s in self.other_letter_seg],
msg="bypass doesn't copy annotations!"
)示例2: test_bypass_deepcopy
# 需要导入模块: from LTTL import Segmenter [as 别名]
# 或者: from LTTL.Segmenter import bypass [as 别名]
def test_bypass_deepcopy(self):
"""Does bypass deep copy input segments?"""
segmentation = Segmenter.bypass(self.letter_seg)
self.assertNotEqual(
segmentation,
self.letter_seg,
msg="bypass doesn't deep copy input segments!"
)示例3: test_bypass_copy_segments
# 需要导入模块: from LTTL import Segmenter [as 别名]
# 或者: from LTTL.Segmenter import bypass [as 别名]
def test_bypass_copy_segments(self):
"""Does bypass copy input segments?"""
segmentation = Segmenter.bypass(self.letter_seg)
self.assertEqual(
[s.get_content() for s in segmentation],
[s.get_content() for s in self.letter_seg],
msg="bypass doesn't copy input segments!"
)