本文整理汇总了Python中lib2to3.pygram.token.INDENT属性的典型用法代码示例。如果您正苦于以下问题：Python token.INDENT属性的具体用法？Python token.INDENT怎么用？Python token.INDENT使用的例子？那么恭喜您, 这里精选的属性代码示例或许可以为您提供帮助。您也可以进一步了解该属性所在类lib2to3.pygram.token的用法示例。
在下文中一共展示了token.INDENT属性的5个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: indentation
# 需要导入模块: from lib2to3.pygram import token [as 别名]
# 或者: from lib2to3.pygram.token import INDENT [as 别名]
def indentation(node):
"""
Returns the indentation for this node
Iff a node is in a suite, then it has indentation.
"""
while node.parent is not None and node.parent.type != syms.suite:
node = node.parent
if node.parent is None:
return u""
# The first three children of a suite are NEWLINE, INDENT, (some other node)
# INDENT.value contains the indentation for this suite
# anything after (some other node) has the indentation as its prefix.
if node.type == token.INDENT:
return node.value
elif node.prev_sibling is not None and node.prev_sibling.type == token.INDENT:
return node.prev_sibling.value
elif node.prev_sibling is None:
return u""
else:
return node.prefix 示例2: suitify
# 需要导入模块: from lib2to3.pygram import token [as 别名]
# 或者: from lib2to3.pygram.token import INDENT [as 别名]
def suitify(parent):
"""
Turn the stuff after the first colon in parent's children
into a suite, if it wasn't already
"""
for node in parent.children:
if node.type == syms.suite:
# already in the prefered format, do nothing
return
# One-liners have no suite node, we have to fake one up
for i, node in enumerate(parent.children):
if node.type == token.COLON:
break
else:
raise ValueError(u"No class suite and no ':'!")
# Move everything into a suite node
suite = Node(syms.suite, [Newline(), Leaf(token.INDENT, indentation(node) + indentation_step(node))])
one_node = parent.children[i+1]
one_node.remove()
one_node.prefix = u''
suite.append_child(one_node)
parent.append_child(suite) 示例3: fixup_indent
# 需要导入模块: from lib2to3.pygram import token [as 别名]
# 或者: from lib2to3.pygram.token import INDENT [as 别名]
def fixup_indent(suite):
""" If an INDENT is followed by a thing with a prefix then nuke the prefix
Otherwise we get in trouble when removing __metaclass__ at suite start
"""
kids = suite.children[::-1]
# find the first indent
while kids:
node = kids.pop()
if node.type == token.INDENT:
break
# find the first Leaf
while kids:
node = kids.pop()
if isinstance(node, Leaf) and node.type != token.DEDENT:
if node.prefix:
node.prefix = u''
return
else:
kids.extend(node.children[::-1]) 示例4: indentation
# 需要导入模块: from lib2to3.pygram import token [as 别名]
# 或者: from lib2to3.pygram.token import INDENT [as 别名]
def indentation(node):
u"""
Returns the indentation for this node
Iff a node is in a suite, then it has indentation.
"""
while node.parent is not None and node.parent.type != syms.suite:
node = node.parent
if node.parent is None:
return u""
# The first three children of a suite are NEWLINE, INDENT, (some other node)
# INDENT.value contains the indentation for this suite
# anything after (some other node) has the indentation as its prefix.
if node.type == token.INDENT:
return node.value
elif node.prev_sibling is not None and node.prev_sibling.type == token.INDENT:
return node.prev_sibling.value
elif node.prev_sibling is None:
return u""
else:
return node.prefix 示例5: suitify
# 需要导入模块: from lib2to3.pygram import token [as 别名]
# 或者: from lib2to3.pygram.token import INDENT [as 别名]
def suitify(parent):
u"""
Turn the stuff after the first colon in parent's children
into a suite, if it wasn't already
"""
for node in parent.children:
if node.type == syms.suite:
# already in the prefered format, do nothing
return
# One-liners have no suite node, we have to fake one up
for i, node in enumerate(parent.children):
if node.type == token.COLON:
break
else:
raise ValueError(u"No class suite and no ':'!")
# Move everything into a suite node
suite = Node(syms.suite, [Newline(), Leaf(token.INDENT, indentation(node) + indentation_step(node))])
one_node = parent.children[i+1]
one_node.remove()
one_node.prefix = u''
suite.append_child(one_node)
parent.append_child(suite)