本文整理汇总了Python中future.utils.PYPY属性的典型用法代码示例。如果您正苦于以下问题：Python utils.PYPY属性的具体用法？Python utils.PYPY怎么用？Python utils.PYPY使用的例子？那么恭喜您, 这里精选的属性代码示例或许可以为您提供帮助。您也可以进一步了解该属性所在类future.utils的用法示例。
在下文中一共展示了utils.PYPY属性的3个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: newround
# 需要导入模块: from future import utils [as 别名]
# 或者: from future.utils import PYPY [as 别名]
def newround(number, ndigits=None):
"""
See Python 3 documentation: uses Banker's Rounding.
Delegates to the __round__ method if for some reason this exists.
If not, rounds a number to a given precision in decimal digits (default
0 digits). This returns an int when called with one argument,
otherwise the same type as the number. ndigits may be negative.
See the test_round method in future/tests/test_builtins.py for
examples.
"""
return_int = False
if ndigits is None:
return_int = True
ndigits = 0
if hasattr(number, '__round__'):
return number.__round__(ndigits)
if ndigits < 0:
raise NotImplementedError('negative ndigits not supported yet')
exponent = Decimal('10') ** (-ndigits)
if PYPY:
# Work around issue #24: round() breaks on PyPy with NumPy's types
if 'numpy' in repr(type(number)):
number = float(number)
if not PY26:
d = Decimal.from_float(number).quantize(exponent,
rounding=ROUND_HALF_EVEN)
else:
d = from_float_26(number).quantize(exponent, rounding=ROUND_HALF_EVEN)
if return_int:
return int(d)
else:
return float(d)
### From Python 2.7's decimal.py. Only needed to support Py2.6: 示例2: newround
# 需要导入模块: from future import utils [as 别名]
# 或者: from future.utils import PYPY [as 别名]
def newround(number, ndigits=None):
"""
See Python 3 documentation: uses Banker's Rounding.
Delegates to the __round__ method if for some reason this exists.
If not, rounds a number to a given precision in decimal digits (default
0 digits). This returns an int when called with one argument,
otherwise the same type as the number. ndigits may be negative.
See the test_round method in future/tests/test_builtins.py for
examples.
"""
return_int = False
if ndigits is None:
return_int = True
ndigits = 0
if hasattr(number, '__round__'):
return number.__round__(ndigits)
if ndigits < 0:
raise NotImplementedError('negative ndigits not supported yet')
exponent = Decimal('10') ** (-ndigits)
if PYPY:
# Work around issue #24: round() breaks on PyPy with NumPy's types
if 'numpy' in repr(type(number)):
number = float(number)
if not PY26:
d = Decimal.from_float(number).quantize(exponent,
rounding=ROUND_HALF_EVEN)
else:
d = from_float_26(number).quantize(exponent, rounding=ROUND_HALF_EVEN)
if return_int:
return int(d)
else:
return float(d)
### From Python 2.7's decimal.py. Only needed to support Py2.6: 示例3: newround
# 需要导入模块: from future import utils [as 别名]
# 或者: from future.utils import PYPY [as 别名]
def newround(number, ndigits=None):
"""
See Python 3 documentation: uses Banker's Rounding.
Delegates to the __round__ method if for some reason this exists.
If not, rounds a number to a given precision in decimal digits (default
0 digits). This returns an int when called with one argument,
otherwise the same type as the number. ndigits may be negative.
See the test_round method in future/tests/test_builtins.py for
examples.
"""
return_int = False
if ndigits is None:
return_int = True
ndigits = 0
if hasattr(number, '__round__'):
return number.__round__(ndigits)
if ndigits < 0:
raise NotImplementedError('negative ndigits not supported yet')
exponent = Decimal('10') ** (-ndigits)
if PYPY:
# Work around issue #24: round() breaks on PyPy with NumPy's types
if 'numpy' in repr(type(number)):
number = float(number)
if isinstance(number, Decimal):
d = number
else:
if not PY26:
d = Decimal.from_float(number).quantize(exponent,
rounding=ROUND_HALF_EVEN)
else:
d = from_float_26(number).quantize(exponent, rounding=ROUND_HALF_EVEN)
if return_int:
return int(d)
else:
return float(d)
### From Python 2.7's decimal.py. Only needed to support Py2.6: