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PHP Settings::isDefaultUserGuest方法代码示例

本文整理汇总了PHP中thebuggenie\core\framework\Settings::isDefaultUserGuest方法的典型用法代码示例。如果您正苦于以下问题:PHP Settings::isDefaultUserGuest方法的具体用法?PHP Settings::isDefaultUserGuest怎么用?PHP Settings::isDefaultUserGuest使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在thebuggenie\core\framework\Settings的用法示例。


在下文中一共展示了Settings::isDefaultUserGuest方法的4个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的PHP代码示例。

示例1: isGuest

 /**
  * Checks whether or not the current user is a "regular" or "guest" user
  *
  * @return boolean
  */
 public function isGuest()
 {
     return (bool) (!$this->isLoggedIn() || $this->getID() == framework\Settings::getDefaultUserID() && framework\Settings::isDefaultUserGuest());
 }
开发者ID:underblaze,项目名称:thebuggenie-4.1.0,代码行数:9,代码来源:User.php

示例2: hasUserVoted

 /**
  * Whether or not the current user has voted
  *
  * @return boolean
  */
 public function hasUserVoted($user_id, $up)
 {
     $user_id = is_object($user_id) ? $user_id->getID() : $user_id;
     $this->_setupVotes();
     if ($user_id == \thebuggenie\core\framework\Settings::getDefaultUserID() && \thebuggenie\core\framework\Settings::isDefaultUserGuest() || !$this->getProject()->canVoteOnIssues()) {
         return true;
     }
     if (array_key_exists($user_id, $this->_votes)) {
         return $up ? (int) $this->_votes[$user_id] > 0 : (int) $this->_votes[$user_id] < 0;
     } else {
         return false;
     }
 }
开发者ID:AzerothShard,项目名称:thebuggenie,代码行数:18,代码来源:Issue.php

示例3: _populateScopeDetails

 protected function _populateScopeDetails()
 {
     if ($this->_unconfirmed_scopes === null || $this->_confirmed_scopes === null) {
         $this->_unconfirmed_scopes = array();
         $this->_confirmed_scopes = array();
         if ($this->_scopes === null) {
             $this->_scopes = array();
         }
         if ($this->getID() == framework\Settings::getDefaultUserID() && framework\Settings::isDefaultUserGuest()) {
             $this->_confirmed_scopes[framework\Context::getScope()->getID()] = framework\Context::getScope();
         } else {
             $scopes = tables\UserScopes::getTable()->getScopeDetailsByUser($this->getID());
             foreach ($scopes as $scope_id => $details) {
                 if (!$details['confirmed']) {
                     $this->_unconfirmed_scopes[$scope_id] = $details['scope'];
                 } else {
                     $this->_confirmed_scopes[$scope_id] = $details['scope'];
                 }
                 if (!array_key_exists($scope_id, $this->_scopes)) {
                     $this->_scopes[$scope_id] = $details['scope'];
                 }
             }
         }
     }
 }
开发者ID:founderio,项目名称:thebuggenie,代码行数:25,代码来源:User.php

示例4: __

 disabled<?php 
}
?>
>
                <option value=1<?php 
if (\thebuggenie\core\framework\Settings::isDefaultUserGuest()) {
    ?>
 selected<?php 
}
?>
><?php 
echo __('No, the default user is a guest account');
?>
</option>
                <option value=0<?php 
if (!\thebuggenie\core\framework\Settings::isDefaultUserGuest()) {
    ?>
 selected<?php 
}
?>
><?php 
echo __('Yes, the default user is a normal account');
?>
</option>
            </select>
            <?php 
echo config_explanation(__('Select if the default user is a guest user or a normal user'));
?>
        </td>
    </tr>
    <tr>
开发者ID:pkdevboxy,项目名称:thebuggenie,代码行数:31,代码来源:_user.inc.php


注:本文中的thebuggenie\core\framework\Settings::isDefaultUserGuest方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。