当前位置: 首页>>代码示例>>PHP>>正文


PHP Users::getPosts方法代码示例

本文整理汇总了PHP中Phosphorum\Models\Users::getPosts方法的典型用法代码示例。如果您正苦于以下问题:PHP Users::getPosts方法的具体用法?PHP Users::getPosts怎么用?PHP Users::getPosts使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在Phosphorum\Models\Users的用法示例。


在下文中一共展示了Users::getPosts方法的3个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的PHP代码示例。

示例1: canHave

 /**
  * Check whether the user can have the badge
  *
  * @param Users $user
  * @return boolean
  */
 public function canHave(Users $user)
 {
     $noBountyCategories = $this->getNoBountyCategories();
     $conditions = 'categories_id NOT IN (' . join(', ', $noBountyCategories) . ') AND accepted_answer = "Y"';
     $posts = $user->getPosts(array($conditions, 'order' => 'created_at DESC'));
     foreach ($posts as $post) {
         $ownReply = $post->countReplies(array("accepted = 'Y' AND users_id = ?0", 'bind' => array($user->id)));
         if ($ownReply) {
             return true;
         }
     }
     return false;
 }
开发者ID:Blkc,项目名称:forum,代码行数:19,代码来源:SelfLearner.php

示例2: canHave

 /**
  * Check whether the user can have the badge
  *
  * @param  Users $user
  * @return boolean
  */
 public function canHave(Users $user)
 {
     $ids = [];
     $noBountyCategories = $this->getNoBountyCategories();
     $conditions = 'categories_id NOT IN (' . join(', ', $noBountyCategories) . ') AND number_views >= 10000';
     $posts = $user->getPosts([$conditions, 'columns' => 'id', 'order' => 'created_at DESC']);
     foreach ($posts as $post) {
         $have = UsersBadges::count(['users_id = ?0 AND badge = ?1 AND type = "P" AND code1 = ?2', 'bind' => [$user->id, $this->getName(), $post->id]]);
         if (!$have) {
             $ids[] = $post->id;
         }
     }
     return $ids;
 }
开发者ID:phalcon,项目名称:forum,代码行数:20,代码来源:FamousQuestion.php

示例3: canHave

 /**
  * Check whether the user can have the badge
  *
  * @param  Users $user
  * @return boolean
  */
 public function canHave(Users $user)
 {
     $ids = array();
     $noBountyCategories = $this->getNoBountyCategories();
     $conditions = 'categories_id NOT IN (' . join(', ', $noBountyCategories) . ') AND
     (IF(votes_up IS NULL, 0, votes_up) - IF(votes_down IS NULL, 0, votes_down)) >= 5';
     $posts = $user->getPosts(array($conditions, 'columns' => 'id', 'order' => 'created_at DESC'));
     foreach ($posts as $post) {
         $have = UsersBadges::count(array('users_id = ?0 AND badge = ?1 AND type = "P" AND code1 = ?2', 'bind' => array($user->id, $this->getName(), $post->id)));
         if (!$have) {
             $ids[] = $post->id;
         }
     }
     return $ids;
 }
开发者ID:kjmtrue,项目名称:phalcon-tip,代码行数:21,代码来源:GoodQuestion.php


注:本文中的Phosphorum\Models\Users::getPosts方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。