本文整理汇总了PHP中AppBundle\Entity\Post::getState方法的典型用法代码示例。如果您正苦于以下问题：PHP Post::getState方法的具体用法？PHP Post::getState怎么用？PHP Post::getState使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类AppBundle\Entity\Post的用法示例。
在下文中一共展示了Post::getState方法的2个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的PHP代码示例。
示例1: isEditGranted
/**
* @param Post $post
* @param User $user
*
* @return bool
*/
private function isEditGranted(Post $post, User $user)
{
switch ($post->getState()) {
case Post::STATUS_DRAFT:
return $post->isAuthor($user);
case Post::STATUS_REVIEW:
return $user->isAdmin();
}
return false;
}示例2: editAction
/**
* Displays a form to edit an existing Post entity.
*
* @Route("/{id}/edit", requirements={"id" = "\d+"}, name="admin_post_edit")
* @Method({"GET", "POST"})
* @Security("has_role('ROLE_USER')")
*/
public function editAction(Post $post, Request $request)
{
if (null === $this->getUser() || !$post->isAuthor($this->getUser())) {
throw $this->createAccessDeniedException('Posts can only be edited by their authors.');
}
if ($post->getState() !== Post::STATUS_DRAFT) {
return $this->redirectToRoute('admin_post_index');
}
$em = $this->getDoctrine()->getManager();
$editForm = $this->createForm(new PostType(), $post);
$deleteForm = $this->createDeleteForm($post);
$editForm->handleRequest($request);
if ($editForm->isSubmitted() && $editForm->isValid()) {
$post->setSlug($this->get('slugger')->slugify($post->getTitle()));
if ($request->request->has('publish')) {
$post->setState(Post::STATUS_VOTING);
}
$em->flush();
return $this->redirectToRoute('admin_post_edit', array('id' => $post->getId()));
}
return $this->render('admin/blog/edit.html.twig', array('post' => $post, 'edit_form' => $editForm->createView(), 'delete_form' => $deleteForm->createView()));
}