本文整理汇总了PHP中App\Repositories\UserRepository::getStatut方法的典型用法代码示例。如果您正苦于以下问题：PHP UserRepository::getStatut方法的具体用法？PHP UserRepository::getStatut怎么用？PHP UserRepository::getStatut使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类App\Repositories\UserRepository的用法示例。
在下文中一共展示了UserRepository::getStatut方法的2个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的PHP代码示例。
示例1: indexOrder
/**
* Display a listing of the resource.
*
* @param Illuminate\Http\Request $request
* @return Response
*/
public function indexOrder(Request $request)
{
$statut = $this->user_gestion->getStatut();
$posts = $this->blog_gestion->index(10, $statut == 'admin' ? null : $request->user()->id, $request->input('name'), $request->input('sens'));
$links = str_replace('/?', '?', $posts->render());
return response()->json(['view' => view('back.blog.table', compact('statut', 'posts'))->render(), 'links' => $links]);
}示例2: indexOrder
/**
* Display a listing of the resource.
*
* @param Illuminate\Http\Request $request
* @return Response
*/
public function indexOrder(Request $request)
{
$statut = $this->user_gestion->getStatut();
$posts = $this->blog_gestion->index(10, $statut == 'admin' ? null : $request->user()->id, $request->name, $request->sens);
$links = $posts->appends(['name' => $request->name, 'sens' => $request->sens]);
if ($request->ajax()) {
return response()->json(['view' => view('back.blog.table', compact('statut', 'posts'))->render(), 'links' => $links->setPath('order')->render()]);
}
$links->setPath('')->render();
$order = (object) ['name' => $request->name, 'sens' => 'sort-' . $request->sens];
return view('back.blog.index', compact('posts', 'links', 'order'));
}