本文整理汇总了PHP中App\Model\User::getRoles方法的典型用法代码示例。如果您正苦于以下问题：PHP User::getRoles方法的具体用法？PHP User::getRoles怎么用？PHP User::getRoles使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类App\Model\User的用法示例。
在下文中一共展示了User::getRoles方法的2个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的PHP代码示例。
示例1: index
/**
* Index action method
*
* @return void
*/
public function index($rid = null)
{
if (null === $rid || $this->services['acl']->isAllowed($this->sess->user->role, 'users-of-role-' . $rid, 'index')) {
$deniedRoles = [];
$resources = $this->services['acl']->getResources();
foreach ($resources as $name => $resource) {
if (!$this->services['acl']->isAllowed($this->sess->user->role, $name, 'index')) {
$deniedRoles[] = (int) substr($name, strrpos($name, '-') + 1);
}
}
$user = new Model\User();
$searchUsername = $this->request->getQuery('search_username');
if ($user->hasPages($this->application->config()['pagination'], $rid, $searchUsername, $deniedRoles)) {
$limit = $this->application->config()['pagination'];
$pages = new Paginator($user->getCount($rid, $searchUsername, $deniedRoles), $limit);
$pages->useInput(true);
} else {
$limit = null;
$pages = null;
}
$this->prepareView('users/index.phtml');
$this->view->title = 'Users';
$this->view->pages = $pages;
$this->view->roleId = $rid;
$this->view->queryString = $this->getQueryString('sort');
$this->view->searchUsername = $searchUsername;
$this->view->users = $user->getAll($rid, $searchUsername, $deniedRoles, $limit, $this->request->getQuery('page'), $this->request->getQuery('sort'));
$this->view->roles = $user->getRoles();
$this->send();
} else {
$this->redirect('/users');
}
}示例2: updateUser
/**
* Sorry this changes will be not persisted.
*
* @param User $user
* @param string $password
*/
public function updateUser(User $user, $password)
{
$this->database[$user->getName()] = ['password' => $this->encode($password), 'roles' => $user->getRoles()];
}