本文整理汇总了PHP中text::parse_ordinal_triplet方法的典型用法代码示例。如果您正苦于以下问题：PHP text::parse_ordinal_triplet方法的具体用法？PHP text::parse_ordinal_triplet怎么用？PHP text::parse_ordinal_triplet使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类text的用法示例。
在下文中一共展示了text::parse_ordinal_triplet方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的PHP代码示例。
示例1: numtostr
/**
* Число прописью
* @version 1.0 beta
*
* @param int $num
* @param int $numeral_type Тип числительного: 1 - количественное, 2 - порядковое
* @param int $case Падеж: 1 - именительный, 2 - родительный, 3 - дательный, 4 - винительный, 5 - творительный, 6 - предложный
* @param int $gender Пол: 1 - мужской, 2 - женский
* @param int $subject_type 1 - неодушевленный, 2 - одушевленный
* @param array $noun таблица со спряжениями сопутствующего существительного
*/
public static function numtostr($num, $numeral_type = 1, $case = 1, $gender = 1, $subject_type = 1, $noun = NULL)
{
$nouns = self::$LIBTEXT_GLOBALS['nouns'];
$str = array();
if (bccomp('1000000000000', $num) != 1 || bccomp($num, '0') != 1) {
return false;
}
// sum must be from 0 to 1 000 000 000 000
if (bccomp($num, '0') == 0) {
}
// TODO: special case, sum is equal to zero
// Fetch triplets one by one from the lowest one
$thresholds = array(1 => '1000', '1000000', '1000000000');
// Define thresholds
// Set initial data
$order = 1;
$triplet = bcmod($num, '1000');
$lowest_nonzero_triplet_found = false;
// indicates declension need for ordinal numerals
while (bccomp($num, '0') == 1) {
if (bccomp($triplet, '0') == 1) {
$with_declension = false;
// Whether to decline the last numerical (for ordinal numerals only)
if (!$lowest_nonzero_triplet_found) {
$with_declension = true;
}
// Define set of nouns
$triplet_noun = NULL;
$triplet_gender = 0;
$triplet_subject_type = 0;
switch ($order) {
case 1:
$triplet_noun = $noun;
$triplet_gender = $gender;
$triplet_subject_type = $subject_type;
break;
case 2:
// Use internal noun for thousands
$triplet_noun = $nouns['thousand'];
$triplet_gender = 2;
$triplet_subject_type = 1;
break;
case 3:
// Use internal noun for millions
$triplet_noun = $nouns['million'];
$triplet_gender = 1;
$triplet_subject_type = 1;
break;
case 4:
// Use internal noun for billions
$triplet_noun = $nouns['billion'];
$triplet_gender = 1;
$triplet_subject_type = 1;
break;
default:
assert(false);
// This must not happen!
}
if ($numeral_type == 1) {
array_unshift($str, text::parse_cardinal_triplet($triplet, $order, $case, $triplet_gender, $triplet_subject_type, $triplet_noun, $with_declension, $noun));
// In this case, with_declension has nothing about declension but indicates the need to add custom noun
// when order is more than 1 (actually, at the end of the result string)
} elseif ($numeral_type == 2) {
array_unshift($str, text::parse_ordinal_triplet($triplet, $order, $case, $triplet_gender, $triplet_subject_type, $triplet_noun, $with_declension, $gender, $subject_type, $noun));
}
if (!$lowest_nonzero_triplet_found) {
$lowest_nonzero_triplet_found = true;
}
}
$num = bcdiv(bcsub($num, $triplet), '1000');
$triplet = bcmod($num, '1000');
$order++;
}
return implode(' ', $str);
}