本文整理汇总了PHP中Zend_Acl_Role_Interface::getId方法的典型用法代码示例。如果您正苦于以下问题：PHP Zend_Acl_Role_Interface::getId方法的具体用法？PHP Zend_Acl_Role_Interface::getId怎么用？PHP Zend_Acl_Role_Interface::getId使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类Zend_Acl_Role_Interface的用法示例。
在下文中一共展示了Zend_Acl_Role_Interface::getId方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的PHP代码示例。
示例1: assert
/**
* Returns true if and only if the assertion conditions are met
*
* This method is passed the ACL, Role, Resource, and privilege to which
* the authorization query applies. If the $role, $resource, or $privilege
* parameters are null, it means that the query applies to all Roles,
* Resources, or privileges, respectively.
*
* @param Zend_Acl $acl
* @param Zend_Acl_Role_Interface $role
* @param Zend_Acl_Resource_Interface $resource
* @param string $privilege
* @return boolean
*/
public function assert(Zend_Acl $acl, Zend_Acl_Role_Interface $role = null, Zend_Acl_Resource_Interface $resource = null, $privilege = null)
{
// We need specific objects to check against each other
if (NULL === $role || NULL === $resource) {
return false;
}
// Ensure we're handled User models
if (!$role instanceof UserModel) {
throw new Exception('Role must be an instance of UserModel');
}
if ($resource instanceof WatcherModel) {
if ($role instanceof \Application\Model\CurrentUserModel && $role->isApiAuthUser()) {
return $role->apiId == $resource->owner;
}
return $role->id === $resource->owner;
}
if ($resource instanceof UserConfigModel) {
return $role->id === $resource->userId;
}
if (!$resource instanceof UserModel) {
throw new Exception('Resource must be an instance of UserModel');
}
return $role->getId() === $resource->getId();
}