本文整理汇总了PHP中Zend_Acl_Resource_Interface::getUserById方法的典型用法代码示例。如果您正苦于以下问题:PHP Zend_Acl_Resource_Interface::getUserById方法的具体用法?PHP Zend_Acl_Resource_Interface::getUserById怎么用?PHP Zend_Acl_Resource_Interface::getUserById使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类Zend_Acl_Resource_Interface
的用法示例。
在下文中一共展示了Zend_Acl_Resource_Interface::getUserById方法的1个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的PHP代码示例。
示例1: assert
/**
* This assertion should receive the actual User objects.
*
* @param Zend_Acl $acl
* @param Zend_Acl_Role_Interface $user
* @param Zend_Acl_Resource_Interface $model
* @param $privilege
* @return bool
*/
public function assert(Zend_Acl $acl, Zend_Acl_Role_Interface $user = null, Zend_Acl_Resource_Interface $model = null, $privilege = null)
{
$request = Zend_Controller_Front::getInstance()->getRequest();
// have to hack this because of the 'oneitem' route all controller/action combo's will execute this assertion
// @todo: change this in the oneitem route somehow?
if ($request->getControllerName() !== 'user') {
return true;
}
$param = $request->getParam('id', null);
if (!$param) {
return true;
}
// perform check
if ($model->getUserById($param)->hasRole(array('presenter', 'chair'))) {
return true;
} else {
return false;
}
}