本文整理汇总了PHP中Sql::get_user_from_id方法的典型用法代码示例。如果您正苦于以下问题：PHP Sql::get_user_from_id方法的具体用法？PHP Sql::get_user_from_id怎么用？PHP Sql::get_user_from_id使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类Sql的用法示例。
在下文中一共展示了Sql::get_user_from_id方法的2个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的PHP代码示例。
示例1: get_logged_in_user
/**
* Get the user name of the currently logged in user, or NULL.
*/
public static function get_logged_in_user()
{
$current_user_id = Authentication::get_current_user_id();
if (Authentication::authenticate_user_by_cookie($current_user_id)) {
$logged_in_user = Sql::get_user_from_id($current_user_id);
} else {
$logged_in_user = NULL;
}
return $logged_in_user;
}示例2:
if ($project_owner) {
$project = Sql::get_project_from_url($project_owner->get_id(), $project_urlname);
}
$tasks = NULL;
$project_name = "<Unknown project>";
$project_owner_name = "<Unknown owner>";
$project_description = "This project does not exist yet.";
$project_id = 0;
$worked_per_week = -1;
$owner_logged_in = FALSE;
if ($project) {
$project_name = $project->get_name();
$project_description = $project->get_description();
$project_id = $project->get_id();
$tasks = Sql::get_tasks_from_project_id($project_id);
$project_owner = Sql::get_user_from_id($project->get_owner_user_id());
$owner_logged_in = Authentication::authenticate_user_by_cookie($project->get_owner_user_id());
$worked_per_week = $project->get_worked_per_week();
if ($project_owner) {
$project_owner_name = $project_owner->get_name();
}
}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title><?php
echo $project_owner_name;
?>
/<?php
echo $project_name;