本文整理汇总了PHP中Source::getSources方法的典型用法代码示例。如果您正苦于以下问题：PHP Source::getSources方法的具体用法？PHP Source::getSources怎么用？PHP Source::getSources使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类Source的用法示例。
在下文中一共展示了Source::getSources方法的2个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的PHP代码示例。
示例1: Source
<?php
require 'include/config.php';
require 'include/class.source.php';
$n = new Source($db);
$sors = $n->getSources();
include 'include/top.php';
?>
<table class="tablesorter">
<thead>
<tr>
<th>ID</th>
<th>Name</th>
</tr>
</thead>
<tbody>
<?php
foreach ($sors as $s) {
?>
<tr>
<td><?php
echo $s['source_id'];
?>
</td>
<td><a href="sources_edit.php?id=<?php
echo $s['source_id'];
?>
"><?php
echo $s['source_name'];示例2: Source
<?php
require 'include/config.php';
require 'include/class.source.php';
$n = new Source($db);
$sors = $n->getSources('bad');
include 'include/top.php';
?>
<table class="tablesorter">
<thead>
<tr>
<th>ID</th>
<th>Name</th>
</tr>
</thead>
<tbody>
<?php
foreach ($sors as $s) {
?>
<tr>
<td><?php
echo $s['source_id'];
?>
</td>
<td><a href="sources_edit.php?id=<?php
echo $s['source_id'];
?>
"><?php
echo $s['source_name'];