本文整理汇总了PHP中Requirements::createRequirementAtom方法的典型用法代码示例。如果您正苦于以下问题：PHP Requirements::createRequirementAtom方法的具体用法？PHP Requirements::createRequirementAtom怎么用？PHP Requirements::createRequirementAtom使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类Requirements的用法示例。
在下文中一共展示了Requirements::createRequirementAtom方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的PHP代码示例。
示例1: updateRequirementAndPackage
public function updateRequirementAndPackage($pack)
{
if (!$pack || !$pack->game_id || !$pack->requirement_and_package_id) {
return;
}
Module::query("UPDATE requirement_and_packages SET " . "game_id = '" . addslashes($pack->game_id) . "'" . ($pack->name ? ", name = '" . addslashes($pack->name) . "'" : "") . " WHERE requirement_and_package_id = '" . addslashes($pack->requirement_and_package_id) . "'");
$sql_currentAtoms = Module::queryArray("SELECT * FROM requirement_atoms WHERE requirement_and_package_id = '{$pack->requirement_and_package_id}'");
for ($i = 0; $i < count($sql_currentAtoms); $i++) {
$matchingAtom = null;
for ($j = 0; $pack->atoms && $j < count($pack->atoms); $j++) {
if ($sql_currentAtoms[$i]->requirement_atom_id == $pack->atoms[$j]->requirement_atom_id) {
$matchingAtom = $pack->atoms[$j];
//remove from array so I can just add all remaining later
array_splice($pack->atoms, $j, 1);
$j--;
}
}
if ($matchingAtom) {
$matchingAtom->requirement_atom_id = $pack->atoms[$j]->requirement_atom_id;
$matchingAtom->game_id = $pack->game_id;
Requirements::updateRequirementAtom($matchingAtom);
} else {
Requirements::deleteRequirementAtom($sql_currentAtoms[$i]->requirement_atom_id);
}
}
for ($i = 0; $pack->atoms && $i < count($pack->atoms); $i++) {
$pack->atoms[$i]->requirement_atom_id = $pack->atoms[$j]->requirement_atom_id;
$pack->atoms[$i]->game_id = $pack->game_id;
Requirements::createRequirementAtom($pack->atoms[$i]);
}
}