本文整理汇总了PHP中Reference::getTableForeignColumnName方法的典型用法代码示例。如果您正苦于以下问题：PHP Reference::getTableForeignColumnName方法的具体用法？PHP Reference::getTableForeignColumnName怎么用？PHP Reference::getTableForeignColumnName使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类Reference的用法示例。
在下文中一共展示了Reference::getTableForeignColumnName方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的PHP代码示例。
示例1: testGetTableForeignColumnName
public function testGetTableForeignColumnName()
{
$expected = 'film_id';
$tableName = 'film';
$row = $this->getMockBuilder(Row::class)->disableOriginalConstructor()->getMock();
$row->expects($this->once())->method('getTableName')->will($this->returnValue($tableName));
$table = $this->getMockBuilder(Table::class)->disableOriginalConstructor()->getMock();
$table->expects($this->once())->method('getForeignKey')->with($this->equalTo($tableName))->will($this->returnValue($expected));
$reference = new Reference($row, $table);
$this->assertEquals($expected, $reference->getTableForeignColumnName(null));
$expected = 'parent_id';
$this->assertEquals($expected, $reference->getTableForeignColumnName($expected));
}