本文整理汇总了PHP中JDatabaseQuery::having方法的典型用法代码示例。如果您正苦于以下问题:PHP JDatabaseQuery::having方法的具体用法?PHP JDatabaseQuery::having怎么用?PHP JDatabaseQuery::having使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类JDatabaseQuery
的用法示例。
在下文中一共展示了JDatabaseQuery::having方法的1个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的PHP代码示例。
示例1: testHaving
/**
* Tests the JDatabaseQuery::having method.
*
* @return void
*
* @covers JDatabaseQuery::having
* @since 11.3
*/
public function testHaving()
{
$this->assertThat(
$this->_instance->having('COUNT(foo) > 1'),
$this->identicalTo($this->_instance),
'Tests chaining.'
);
$this->assertThat(
trim($this->_instance->having),
$this->equalTo('HAVING COUNT(foo) > 1'),
'Tests rendered value.'
);
// Add another column.
$this->_instance->having('COUNT(bar) > 2');
$this->assertThat(
trim($this->_instance->having),
$this->equalTo('HAVING COUNT(foo) > 1 AND COUNT(bar) > 2'),
'Tests rendered value after second use.'
);
// Reset the field to test the glue.
$this->_instance->having = null;
$this->_instance->having('COUNT(foo) > 1', 'OR');
$this->_instance->having('COUNT(bar) > 2');
$this->assertThat(
trim($this->_instance->having),
$this->equalTo('HAVING COUNT(foo) > 1 OR COUNT(bar) > 2'),
'Tests rendered value with OR glue.'
);
}