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PHP JDatabaseQuery::having方法代码示例

本文整理汇总了PHP中JDatabaseQuery::having方法的典型用法代码示例。如果您正苦于以下问题:PHP JDatabaseQuery::having方法的具体用法?PHP JDatabaseQuery::having怎么用?PHP JDatabaseQuery::having使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在JDatabaseQuery的用法示例。


在下文中一共展示了JDatabaseQuery::having方法的1个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的PHP代码示例。

示例1: testHaving

	/**
	 * Tests the JDatabaseQuery::having method.
	 *
	 * @return  void
	 *
	 * @covers  JDatabaseQuery::having
	 * @since   11.3
	 */
	public function testHaving()
	{
		$this->assertThat(
			$this->_instance->having('COUNT(foo) > 1'),
			$this->identicalTo($this->_instance),
			'Tests chaining.'
		);

		$this->assertThat(
			trim($this->_instance->having),
			$this->equalTo('HAVING COUNT(foo) > 1'),
			'Tests rendered value.'
		);

		// Add another column.
		$this->_instance->having('COUNT(bar) > 2');

		$this->assertThat(
			trim($this->_instance->having),
			$this->equalTo('HAVING COUNT(foo) > 1 AND COUNT(bar) > 2'),
			'Tests rendered value after second use.'
		);

		// Reset the field to test the glue.
		$this->_instance->having = null;
		$this->_instance->having('COUNT(foo) > 1', 'OR');
		$this->_instance->having('COUNT(bar) > 2');

		$this->assertThat(
			trim($this->_instance->having),
			$this->equalTo('HAVING COUNT(foo) > 1 OR COUNT(bar) > 2'),
			'Tests rendered value with OR glue.'
		);
	}
开发者ID:realityking,项目名称:joomla-platform,代码行数:42,代码来源:JDatabaseQueryTest.php


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