本文整理汇总了PHP中JComments::getCommentsReportForm方法的典型用法代码示例。如果您正苦于以下问题:PHP JComments::getCommentsReportForm方法的具体用法?PHP JComments::getCommentsReportForm怎么用?PHP JComments::getCommentsReportForm使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类JComments
的用法示例。
在下文中一共展示了JComments::getCommentsReportForm方法的2个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的PHP代码示例。
示例1: showReportForm
function showReportForm($id, $target)
{
if (JCommentsSecurity::badRequest() == 1) {
JCommentsSecurity::notAuth();
}
$response =& JCommentsFactory::getAjaxResponse();
$db =& JCommentsFactory::getDBO();
$comment = new JCommentsDB($db);
if ($comment->load($id)) {
$form = JComments::getCommentsReportForm($id, $comment->object_id, $comment->object_group);
$response->addAssign($target, 'innerHTML', $form);
}
return $response;
}
示例2: showReportForm
public static function showReportForm($id, $target)
{
if (JCommentsSecurity::badRequest() == 1) {
JCommentsSecurity::notAuth();
}
$config = JCommentsFactory::getConfig();
if ($config->getInt('report_reason_required') == 0) {
$_POST['commentid'] = (int) $id;
$response = JCommentsFactory::getAjaxResponse();
$response->addAssign($target, 'innerHTML', '<div id="comments-report-form"></div>');
return self::reportComment();
} else {
$response = JCommentsFactory::getAjaxResponse();
$db = JCommentsFactory::getDBO();
$comment = new JCommentsTableComment($db);
if ($comment->load($id)) {
$form = JComments::getCommentsReportForm($id, $comment->object_id, $comment->object_group);
$response->addAssign($target, 'innerHTML', $form);
}
return $response;
}
}