本文整理汇总了PHP中DatabaseOperation::getUser方法的典型用法代码示例。如果您正苦于以下问题：PHP DatabaseOperation::getUser方法的具体用法？PHP DatabaseOperation::getUser怎么用？PHP DatabaseOperation::getUser使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类DatabaseOperation的用法示例。
在下文中一共展示了DatabaseOperation::getUser方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的PHP代码示例。
示例1: DatabaseOperation
* Check for post request
*/
require_once "classes/DatabaseOperation.php";
if (isset($_POST["request"]) && $_POST["request"] != "") {
//get request
$request = $_POST["request"];
$operation = new DatabaseOperation();
//response array
$response = array("request" => $request, "success" => 0, "error" => 0);
//check for tag type
if ($request == "login") {
//the user has requested to log in
$email = $_POST["email"];
$password = $_POST["password"];
//check if the user has already been registered
if ($user = $operation->getUser($email, $password)) {
//user found
//echo JSON with success
$response["success"] = 1;
$response["unique_id"] = $user["_unique_id"];
$response["user"]["name"] = $user["_name"];
$response["user"]["email"] = $user["_email"];
$response["user"]["created_at"] = $user["_created_at"];
$response["user"]["updated_at"] = $user["_updated_at"];
echo json_encode($response);
} else {
//user not found
//echo JSON with error 1
$response["error"] = 1;
$response["error_message"] = "Incorrect email or password";
echo json_encode($response);