本文整理汇总了PHP中ConsoleOptionParser::subcommands方法的典型用法代码示例。如果您正苦于以下问题：PHP ConsoleOptionParser::subcommands方法的具体用法？PHP ConsoleOptionParser::subcommands怎么用？PHP ConsoleOptionParser::subcommands使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类ConsoleOptionParser的用法示例。
在下文中一共展示了ConsoleOptionParser::subcommands方法的2个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的PHP代码示例。
示例1: testRemoveSubcommand
/**
* test removeSubcommand with an object.
*
* @return void
*/
public function testRemoveSubcommand()
{
$parser = new ConsoleOptionParser('test', FALSE);
$parser->addSubcommand(new ConsoleInputSubcommand('test'));
$result = $parser->subcommands();
$this->assertEquals(1, count($result));
$parser->removeSubcommand('test');
$result = $parser->subcommands();
$this->assertEquals(0, count($result), 'Remove a subcommand does not work');
}示例2: testAddSubcommandObject
/**
* test addSubcommand with an object.
*
* @return void
*/
public function testAddSubcommandObject()
{
$parser = new ConsoleOptionParser('test', false);
$parser->addSubcommand(new ConsoleInputSubcommand('test'));
$result = $parser->subcommands();
$this->assertEquals(1, count($result));
$this->assertEquals('test', $result['test']->name());
}