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PHP Companies::getTable方法代码示例

本文整理汇总了PHP中Companies::getTable方法的典型用法代码示例。如果您正苦于以下问题:PHP Companies::getTable方法的具体用法?PHP Companies::getTable怎么用?PHP Companies::getTable使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在Companies的用法示例。


在下文中一共展示了Companies::getTable方法的1个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的PHP代码示例。

示例1: implode

    $ids = "IN (" . implode(",", array_unique($_POST['id'])) . ")";
    $member_ids = "IN (" . implode(",", array_unique($_POST['member_id'])) . ")";
    $sql = "UPDATE {$tb_prefix}members m,{$tb_prefix}companies c SET c.cache_membergroupid='{$_POST['set_group']}',m.membergroup_id='{$_POST['set_group']}' WHERE c.member_id=m.id AND c.id " . $ids . " AND m.id " . $member_ids;
    $pdb->Execute($sql);
}
if (isset($_POST['recommend'])) {
    foreach ($_POST['id'] as $val) {
        $commend_now = $company->field("if_commend", "id=" . $val);
        if ($commend_now == "0") {
            $result = $company->saveField("if_commend", "1", intval($val));
        } else {
            $result = $company->saveField("if_commend", "0", intval($val));
        }
    }
    $company_ids = implode(",", $_POST['id']);
    $result = $pdb->Execute("update " . $company->getTable() . " set status='1' where id in (" . $company_ids . ")");
    if ($result) {
        flash("success");
    } else {
        flash();
    }
}
if (isset($_POST['save'])) {
    $company_id = $_POST['id'];
    $vals = $_POST['data']['company'];
    if (isset($_POST['manage_type'])) {
        $managetype = implode(",", $_POST['manage_type']);
        $vals['manage_type'] = $managetype;
    }
    if (isset($_POST['FoundDate'])) {
        $vals['found_date'] = Times::dateConvert($_POST['FoundDate']);
开发者ID:renduples,项目名称:alibtob,代码行数:31,代码来源:company.php


注:本文中的Companies::getTable方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。