本文整理汇总了PHP中Bundle::name方法的典型用法代码示例。如果您正苦于以下问题:PHP Bundle::name方法的具体用法?PHP Bundle::name怎么用?PHP Bundle::name使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类Bundle
的用法示例。
在下文中一共展示了Bundle::name方法的5个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的PHP代码示例。
示例1: path
/**
* Get the path to a view on disk.
*
* @param $view
*
* @return string
* @throws \Exception
*/
protected function path($view)
{
$root = \Bundle::path(\Bundle::name($view)) . 'views';
$path = $root . DS . \Bundle::element($view);
if (file_exists($path)) {
return $path;
}
throw new \Exception("View [{$view}] does not exist.");
}
示例2: parse
/**
* Parse a language key into its bundle, file, and line segments.
*
* Language lines follow a {bundle}::{file}.{line} naming convention.
*
* @param string $key
* @return array
*/
protected function parse($key)
{
$bundle = Bundle::name($key);
$segments = explode('.', Bundle::element($key));
// If there are not at least two segments in the array, it means that
// the developer is requesting the entire language line array to be
// returned. If that is the case, we'll make the item "null".
if (count($segments) >= 2) {
$line = implode('.', array_slice($segments, 1));
return array($bundle, $segments[0], $line);
} else {
return array($bundle, $segments[0], null);
}
}
示例3: parse
/**
* Parse a key and return its bundle, file, and key segments.
*
* Configuration items are named using the {bundle}::{file}.{item} convention.
*
* @param string $key
* @return array
*/
protected static function parse($key)
{
// First, we'll check the keyed cache of configuration items, as this will
// be the fastest method of retrieving the configuration option. After an
// item is parsed, it is always stored in the cache by its key.
if (array_key_exists($key, static::$cache)) {
return static::$cache[$key];
}
$bundle = Bundle::name($key);
$segments = explode('.', Bundle::element($key));
// If there are not at least two segments in the array, it means that the
// developer is requesting the entire configuration array to be returned.
// If that is the case, we'll make the item field "null".
if (count($segments) >= 2) {
$parsed = array($bundle, $segments[0], implode('.', array_slice($segments, 1)));
} else {
$parsed = array($bundle, $segments[0], null);
}
return static::$cache[$key] = $parsed;
}
示例4: testBundleNameCanBeRetrievedFromIdentifier
/**
* Test the Bundle::name method.
*
* @group laravel
*/
public function testBundleNameCanBeRetrievedFromIdentifier()
{
$this->assertEquals(DEFAULT_BUNDLE, Bundle::name('something'));
$this->assertEquals(DEFAULT_BUNDLE, Bundle::name('something.else'));
$this->assertEquals('bundle', Bundle::name('bundle::something.else'));
}
示例5: factory
static function factory($block, $fail = true)
{
if (is_object($block)) {
$class = $block;
} else {
\Bundle::start(\Bundle::resolve(\Bundle::name($block)));
if (\IoC::registered($ioc = "vane.block: {$block}")) {
$class = $block = IoC::resolve($ioc);
} else {
$class = static::classOf($block, false);
class_exists($class) or $class = static::fromStd($block);
}
}
if ($fail and !is_subclass_of($class, $parent = 'Laravel\\Routing\\Controller')) {
throw new Error("Block class [{$class}] must inherit from [{$parent}].");
} else {
return is_object($block) ? $block : new $class();
}
}