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Java EncryptionKey.findKey方法代码示例

本文整理汇总了Java中sun.security.krb5.EncryptionKey.findKey方法的典型用法代码示例。如果您正苦于以下问题:Java EncryptionKey.findKey方法的具体用法?Java EncryptionKey.findKey怎么用?Java EncryptionKey.findKey使用的例子?那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在sun.security.krb5.EncryptionKey的用法示例。


在下文中一共展示了EncryptionKey.findKey方法的3个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Java代码示例。

示例1: getDefaults

import sun.security.krb5.EncryptionKey; //导入方法依赖的package包/类
/**
 * Retrieve the default etypes from the configuration file for
 * those etypes for which there are corresponding keys.
 * Used in scenario we have some keys from a keytab with etypes
 * different from those named in configName. Then, in order
 * to decrypt an AS-REP, we should only ask for etypes for which
 * we have keys.
 */
public static int[] getDefaults(String configName, EncryptionKey[] keys)
        throws KrbException {
    int[] answer = getDefaults(configName);

    List<Integer> list = new ArrayList<>(answer.length);
    for (int i = 0; i < answer.length; i++) {
        if (EncryptionKey.findKey(answer[i], keys) != null) {
            list.add(answer[i]);
        }
    }
    int len = list.size();
    if (len <= 0) {
        StringBuffer keystr = new StringBuffer();
        for (int i = 0; i < keys.length; i++) {
            keystr.append(toString(keys[i].getEType()));
            keystr.append(" ");
        }
        throw new KrbException(
            "Do not have keys of types listed in " + configName +
            " available; only have keys of following type: " +
            keystr.toString());
    } else {
        answer = new int[len];
        for (int i = 0; i < len; i++) {
            answer[i] = list.get(i);
        }
        return answer;
    }
}
 
开发者ID:SunburstApps,项目名称:OpenJSharp,代码行数:38,代码来源:EType.java

示例2: getDefaults

import sun.security.krb5.EncryptionKey; //导入方法依赖的package包/类
/**
 * Retrieve the default etypes from the configuration file for
 * those etypes for which there are corresponding keys.
 * Used in scenario we have some keys from a keytab with etypes
 * different from those named in configName. Then, in order
 * to decrypt an AS-REP, we should only ask for etypes for which
 * we have keys.
 */
public static int[] getDefaults(String configName, EncryptionKey[] keys)
        throws KrbException {
    int[] answer = getDefaults(configName);

    List<Integer> list = new ArrayList<>(answer.length);
    for (int i = 0; i < answer.length; i++) {
        if (EncryptionKey.findKey(answer[i], keys) != null) {
            list.add(answer[i]);
        }
    }
    int len = list.size();
    if (len <= 0) {
        StringBuilder keystr = new StringBuilder();
        for (int i = 0; i < keys.length; i++) {
            keystr.append(toString(keys[i].getEType()));
            keystr.append(" ");
        }
        throw new KrbException(
            "Do not have keys of types listed in " + configName +
            " available; only have keys of following type: " +
            keystr.toString());
    } else {
        answer = new int[len];
        for (int i = 0; i < len; i++) {
            answer[i] = list.get(i);
        }
        return answer;
    }
}
 
开发者ID:AdoptOpenJDK,项目名称:openjdk-jdk10,代码行数:38,代码来源:EType.java

示例3: getDefaults

import sun.security.krb5.EncryptionKey; //导入方法依赖的package包/类
/**
 * Retrieve the default etypes from the configuration file for
 * those etypes for which there are corresponding keys.
 * Used in scenario we have some keys from a keytab with etypes
 * different from those named in configName. Then, in order
 * to decrypt an AS-REP, we should only ask for etypes for which
 * we have keys.
 */
public static int[] getDefaults(String configName, EncryptionKey[] keys)
    throws KrbException {
    int[] answer = getDefaults(configName);
    if (answer == null) {
        throw new KrbException("No supported encryption types listed in "
            + configName);
    }

    List<Integer> list = new ArrayList<>(answer.length);
    for (int i = 0; i < answer.length; i++) {
        if (EncryptionKey.findKey(answer[i], keys) != null) {
            list.add(answer[i]);
        }
    }
    int len = list.size();
    if (len <= 0) {
        StringBuffer keystr = new StringBuffer();
        for (int i = 0; i < keys.length; i++) {
            keystr.append(toString(keys[i].getEType()));
            keystr.append(" ");
        }
        throw new KrbException(
            "Do not have keys of types listed in " + configName +
            " available; only have keys of following type: " +
            keystr.toString());
    } else {
        answer = new int[len];
        for (int i = 0; i < len; i++) {
            answer[i] = list.get(i);
        }
        return answer;
    }
}
 
开发者ID:openjdk,项目名称:jdk7-jdk,代码行数:42,代码来源:EType.java


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