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Java Font2D.getNumGlyphs方法代码示例

本文整理汇总了Java中sun.font.Font2D.getNumGlyphs方法的典型用法代码示例。如果您正苦于以下问题:Java Font2D.getNumGlyphs方法的具体用法?Java Font2D.getNumGlyphs怎么用?Java Font2D.getNumGlyphs使用的例子?那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在sun.font.Font2D的用法示例。


在下文中一共展示了Font2D.getNumGlyphs方法的2个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Java代码示例。

示例1: getGlyphToCharMapForFont

import sun.font.Font2D; //导入方法依赖的package包/类
private static char[] getGlyphToCharMapForFont(Font2D font2D) {
    /* NB Composites report the number of glyphs in slot 0.
     * So if a string uses a char from a later slot, or a fallback slot,
     * it will not be able to use this faster path.
     */
    int numGlyphs = font2D.getNumGlyphs();
    int missingGlyph = font2D.getMissingGlyphCode();
    char[] glyphToCharMap = new char[numGlyphs];
    int glyph;

    for (int i=0;i<numGlyphs; i++) {
        glyphToCharMap[i] = CharToGlyphMapper.INVISIBLE_GLYPH_ID;
    }

    /* Consider refining the ranges to try to map by asking the font
     * what ranges it supports.
     * Since a glyph may be mapped by multiple code points, and this
     * code can't handle that, we always prefer the earlier code point.
     */
    for (char c=0; c<0xFFFF; c++) {
       if (c >= CharToGlyphMapper.HI_SURROGATE_START &&
           c <= CharToGlyphMapper.LO_SURROGATE_END) {
            continue;
        }
        glyph = font2D.charToGlyph(c);
        if (glyph != missingGlyph &&
            glyph >= 0 && glyph < numGlyphs &&
            (glyphToCharMap[glyph] ==
             CharToGlyphMapper.INVISIBLE_GLYPH_ID)) {
            glyphToCharMap[glyph] = c;
        }
    }
    return glyphToCharMap;
}
 
开发者ID:SunburstApps,项目名称:OpenJSharp,代码行数:35,代码来源:PathGraphics.java

示例2: getGlyphToCharMapForFont

import sun.font.Font2D; //导入方法依赖的package包/类
private static char[] getGlyphToCharMapForFont(Font2D font2D) {
    /* NB Composites report the number of glyphs in slot 0.
     * So if a string uses a char from a later slot, or a fallback slot,
     * it will not be able to use this faster path.
     */
    int numGlyphs = font2D.getNumGlyphs();
    int missingGlyph = font2D.getMissingGlyphCode();
    char[] glyphToCharMap = new char[numGlyphs];
    int glyph;

    for (int i=0;i<numGlyphs; i++) {
        glyphToCharMap[i] = CharToGlyphMapper.INVISIBLE_GLYPH_ID;
    }

    /* Consider refining the ranges to try to map by asking the font
     * what ranges it supports.
     * Since a glyph may be mapped by multiple code points, and this
     * code can't handle that, we always prefer the earlier code point.
     */
    for (char c=0; c<0xFFFF; c++) {
       if (c >= CharToGlyphMapper.HI_SURROGATE_START &&
           c <= CharToGlyphMapper.LO_SURROGATE_END) {
            continue;
        }
        glyph = font2D.charToGlyph(c);
        if (glyph != missingGlyph && glyph < numGlyphs &&
            (glyphToCharMap[glyph] ==
             CharToGlyphMapper.INVISIBLE_GLYPH_ID)) {
            glyphToCharMap[glyph] = c;
        }
    }
    return glyphToCharMap;
}
 
开发者ID:openjdk,项目名称:jdk7-jdk,代码行数:34,代码来源:PathGraphics.java


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