本文整理汇总了Java中sun.awt.geom.Crossings.accumulateLine方法的典型用法代码示例。如果您正苦于以下问题：Java Crossings.accumulateLine方法的具体用法？Java Crossings.accumulateLine怎么用？Java Crossings.accumulateLine使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类sun.awt.geom.Crossings的用法示例。
在下文中一共展示了Crossings.accumulateLine方法的3个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Java代码示例。
示例1: getCrossings
import sun.awt.geom.Crossings; //导入方法依赖的package包/类
private Crossings getCrossings(double xlo, double ylo,
double xhi, double yhi)
{
Crossings cross = new Crossings.EvenOdd(xlo, ylo, xhi, yhi);
int lastx = xpoints[npoints - 1];
int lasty = ypoints[npoints - 1];
int curx, cury;
// Walk the edges of the polygon
for (int i = 0; i < npoints; i++) {
curx = xpoints[i];
cury = ypoints[i];
if (cross.accumulateLine(lastx, lasty, curx, cury)) {
return null;
}
lastx = curx;
lasty = cury;
}
return cross;
}
示例2: getCrossings
import sun.awt.geom.Crossings; //导入方法依赖的package包/类
private Crossings getCrossings(double xlo, double ylo,
double xhi, double yhi)
{
Crossings cross = new Crossings.EvenOdd(xlo, ylo, xhi, yhi);
int lastx = xpoints[npoints - 1];
int lasty = ypoints[npoints - 1];
int curx, cury;
// Walk the edges of the polygon
for (int i = 0; i < npoints; i++) {
curx = xpoints[i];
cury = ypoints[i];
if (cross.accumulateLine(lastx, lasty, curx, cury)) {
return null;
}
lastx = curx;
lasty = cury;
}
return cross;
}
示例3: getCrossings
import sun.awt.geom.Crossings; //导入方法依赖的package包/类
@Nullable
private Crossings getCrossings(double xlo, double ylo,
double xhi, double yhi) {
Crossings cross = new Crossings.EvenOdd(xlo, ylo, xhi, yhi);
double lastx = xpoints[npoints - 1];
double lasty = ypoints[npoints - 1];
double curx, cury;
// Walk the edges of the polygon
for (int i = 0; i < npoints; i++) {
curx = xpoints[i];
cury = ypoints[i];
if (cross.accumulateLine(lastx, lasty, curx, cury)) {
return null;
}
lastx = curx;
lasty = cury;
}
return cross;
}