本文整理汇总了Java中org.sbml.jsbml.ASTNode.isFunction方法的典型用法代码示例。如果您正苦于以下问题：Java ASTNode.isFunction方法的具体用法？Java ASTNode.isFunction怎么用？Java ASTNode.isFunction使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类org.sbml.jsbml.ASTNode的用法示例。
在下文中一共展示了ASTNode.isFunction方法的3个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Java代码示例。
示例1: getSatisfyingNodes
import org.sbml.jsbml.ASTNode; //导入方法依赖的package包/类
/**
* recursively puts the nodes that have the same name as the quarry string
* passed in into the arraylist passed in so, the entire tree is searched
* through, which i don't think is possible with the jsbml methods
*
* @param node
* node to search through
* @param quarry
* string to search for
* @param satisfyingNodes
* list of nodes that satisfy the condition
*/
static void getSatisfyingNodes(ASTNode node, String quarry, ArrayList<ASTNode> satisfyingNodes)
{
if (node.isName() && node.getName().equals(quarry))
{
satisfyingNodes.add(node);
}
else if (node.isFunction() && node.getName().equals(quarry))
{
satisfyingNodes.add(node);
}
else
{
for (ASTNode childNode : node.getChildren())
{
getSatisfyingNodes(childNode, quarry, satisfyingNodes);
}
}
}
示例2: getSatisfyingNodesLax
import org.sbml.jsbml.ASTNode; //导入方法依赖的package包/类
/**
* recursively puts the nodes that have the same name as the quarry string
* passed in into the arraylist passed in so, the entire tree is searched
* through, which i don't think is possible with the jsbml methods the lax
* version uses contains instead of equals
*
* @param node
* node to search through
* @param quarry
* string to search for
* @param satisfyingNodes
* list of nodes that satisfy the condition
*/
void getSatisfyingNodesLax(ASTNode node, String quarry, ArrayList<ASTNode> satisfyingNodes)
{
if (node.isName() && node.getName().contains(quarry))
{
satisfyingNodes.add(node);
}
else if (node.isFunction() && node.getName().contains(quarry))
{
satisfyingNodes.add(node);
}
else
{
for (ASTNode childNode : node.getChildren())
{
getSatisfyingNodesLax(childNode, quarry, satisfyingNodes);
}
}
}
示例3: inlineFormula
import org.sbml.jsbml.ASTNode; //导入方法依赖的package包/类
/**
* inlines a formula with function definitions
*
* @param formula
* @return
*/
protected ASTNode inlineFormula(ASTNode formula)
{
if (formula.isFunction() == false || formula.isOperator()/* || formula.isLeaf() == false */)
{
for (int i = 0; i < formula.getChildCount(); ++i)
{
formula.replaceChild(i, inlineFormula(formula.getChild(i)));// .clone()));
}
}
else if (formula.isFunction() && model.getFunctionDefinition(formula.getName()) != null)
{
if (ibiosimFunctionDefinitions.contains(formula.getName()))
{
return formula;
}
ASTNode inlinedFormula = model.getFunctionDefinition(formula.getName()).getBody().clone();
ASTNode oldFormula = formula.clone();
ArrayList<ASTNode> inlinedChildren = new ArrayList<ASTNode>();
this.getAllASTNodeChildren(inlinedFormula, inlinedChildren);
if (inlinedChildren.size() == 0)
{
inlinedChildren.add(inlinedFormula);
}
HashMap<String, Integer> inlinedChildToOldIndexMap = new HashMap<String, Integer>();
for (int i = 0; i < model.getFunctionDefinition(formula.getName()).getArgumentCount(); ++i)
{
inlinedChildToOldIndexMap.put(model.getFunctionDefinition(formula.getName()).getArgument(i).getName(), i);
}
for (int i = 0; i < inlinedChildren.size(); ++i)
{
ASTNode child = inlinedChildren.get(i);
if (child.isLeaf() && child.isName())
{
int index = inlinedChildToOldIndexMap.get(child.getName());
replaceArgument(inlinedFormula, child.toFormula(), oldFormula.getChild(index));
if (inlinedFormula.getChildCount() == 0)
{
inlinedFormula = oldFormula.getChild(index);
}
}
}
return inlinedFormula;
}
return formula;
}