本文整理汇总了Java中org.pentaho.di.core.row.ValueMetaInterface.isInteger方法的典型用法代码示例。如果您正苦于以下问题：Java ValueMetaInterface.isInteger方法的具体用法？Java ValueMetaInterface.isInteger怎么用？Java ValueMetaInterface.isInteger使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类org.pentaho.di.core.row.ValueMetaInterface的用法示例。
在下文中一共展示了ValueMetaInterface.isInteger方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Java代码示例。
示例1: addCumulativeAverages
import org.pentaho.di.core.row.ValueMetaInterface; //导入方法依赖的package包/类
private void addCumulativeAverages(Object[] row) throws KettleValueException {
// We need to adjust this row with cumulative sums
//
for (int i=0;i<data.cumulativeAvgSourceIndexes.size();i++)
{
int sourceIndex = data.cumulativeAvgSourceIndexes.get(i);
Object previousTarget = data.previousAvgSum[i];
Object sourceValue = row[sourceIndex];
int targetIndex = data.cumulativeAvgTargetIndexes.get(i);
ValueMetaInterface sourceMeta = data.inputRowMeta.getValueMeta(sourceIndex);
ValueMetaInterface targetMeta = data.outputRowMeta.getValueMeta(targetIndex);
// If the first values where null, or this is the first time around, just take the source value...
//
Object sum = null;
if (targetMeta.isNull(previousTarget))
{
sum=sourceMeta.convertToNormalStorageType(sourceValue);
}
else
{
// If the source value is null, just take the previous target value
//
if (sourceMeta.isNull(sourceValue))
{
sum = previousTarget;
}
else
{
if (sourceMeta.isInteger())
{
sum = ValueDataUtil.plus(data.valueMetaInteger, data.previousAvgSum[i], sourceMeta, row[sourceIndex]);
}
else
{
sum = ValueDataUtil.plus(targetMeta, data.previousAvgSum[i], sourceMeta, row[sourceIndex]);
}
}
}
data.previousAvgSum[i] = sum;
if (!sourceMeta.isNull(sourceValue)) data.previousAvgCount[i]++;
if (sourceMeta.isInteger()) {
// Change to number as the exception
//
if (sum==null)
{
row[targetIndex] = null;
}
else
{
row[targetIndex] = new Double( ((Long)sum).doubleValue() / data.previousAvgCount[i] );
}
}
else
{
row[targetIndex] = ValueDataUtil.divide(targetMeta, sum, data.valueMetaInteger, data.previousAvgCount[i]);
}
}
}