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Java MultiUserChatService.getServiceName方法代码示例

本文整理汇总了Java中org.jivesoftware.openfire.muc.MultiUserChatService.getServiceName方法的典型用法代码示例。如果您正苦于以下问题:Java MultiUserChatService.getServiceName方法的具体用法?Java MultiUserChatService.getServiceName怎么用?Java MultiUserChatService.getServiceName使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在org.jivesoftware.openfire.muc.MultiUserChatService的用法示例。


在下文中一共展示了MultiUserChatService.getServiceName方法的2个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Java代码示例。

示例1: ServiceInfo

import org.jivesoftware.openfire.muc.MultiUserChatService; //导入方法依赖的package包/类
public ServiceInfo(MultiUserChatService service) {
    this.subdomain = service.getServiceName();
    this.description = service.getDescription();
    this.isHidden = service.isHidden();
    rooms = new ArrayList<>();
    // Get rooms that have occupants and include them in the reply
    for (MUCRoom room : service.getChatRooms()) {
        LocalMUCRoom localRoom = (LocalMUCRoom) room;
        if (!room.getOccupants().isEmpty()) {
            rooms.add(new RoomInfo(localRoom, localRoom.getOccupants()));
        }
    }
}
 
开发者ID:igniterealtime,项目名称:Openfire,代码行数:14,代码来源:ServiceInfo.java

示例2: ServiceInfo

import org.jivesoftware.openfire.muc.MultiUserChatService; //导入方法依赖的package包/类
public ServiceInfo(MultiUserChatService service) {
    this.subdomain = service.getServiceName();
    this.description = service.getDescription();
    this.isHidden = service.isHidden();
    rooms = new ArrayList<RoomInfo>();
    // Get rooms that have occupants and include them in the reply
    for (MUCRoom room : service.getChatRooms()) {
        LocalMUCRoom localRoom = (LocalMUCRoom) room;
        if (!room.getOccupants().isEmpty()) {
            rooms.add(new RoomInfo(localRoom, localRoom.getOccupants()));
        }
    }
}
 
开发者ID:coodeer,项目名称:g3server,代码行数:14,代码来源:ServiceInfo.java


注:本文中的org.jivesoftware.openfire.muc.MultiUserChatService.getServiceName方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。