本文整理汇总了Java中org.jbox2d.pooling.IDynamicStack.push方法的典型用法代码示例。如果您正苦于以下问题：Java IDynamicStack.push方法的具体用法？Java IDynamicStack.push怎么用？Java IDynamicStack.push使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类org.jbox2d.pooling.IDynamicStack的用法示例。
在下文中一共展示了IDynamicStack.push方法的3个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Java代码示例。
示例1: pushContact
import org.jbox2d.pooling.IDynamicStack; //导入方法依赖的package包/类
public void pushContact(Contact contact) {
Fixture fixtureA = contact.getFixtureA();
Fixture fixtureB = contact.getFixtureB();
if (contact.m_manifold.pointCount > 0 && !fixtureA.isSensor() && !fixtureB.isSensor()) {
fixtureA.getBody().setAwake(true);
fixtureB.getBody().setAwake(true);
}
ShapeType type1 = fixtureA.getType();
ShapeType type2 = fixtureB.getType();
IDynamicStack<Contact> creator = contactStacks[type1.ordinal()][type2.ordinal()].creator;
creator.push(contact);
}
示例2: pushContact
import org.jbox2d.pooling.IDynamicStack; //导入方法依赖的package包/类
public void pushContact(Contact contact) {
if (contact.m_manifold.pointCount > 0) {
contact.getFixtureA().getBody().setAwake(true);
contact.getFixtureB().getBody().setAwake(true);
}
ShapeType type1 = contact.getFixtureA().getType();
ShapeType type2 = contact.getFixtureB().getType();
IDynamicStack<Contact> creator = contactStacks[type1.intValue][type2.intValue].creator;
creator.push(contact);
}
示例3: pushContact
import org.jbox2d.pooling.IDynamicStack; //导入方法依赖的package包/类
public void pushContact(Contact contact) {
Fixture fixtureA = contact.getFixtureA();
Fixture fixtureB = contact.getFixtureB();
if (contact.m_manifold.pointCount > 0 && !fixtureA.isSensor() && !fixtureB.isSensor()) {
fixtureA.getBody().setAwake(true);
fixtureB.getBody().setAwake(true);
}
ShapeType type1 = fixtureA.getType();
ShapeType type2 = fixtureB.getType();
IDynamicStack<Contact> creator = contactStacks[type1.ordinal()][type2.ordinal()].creator;
creator.push(contact);
}